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3 years ago

HELP!!! i need it asap, thank you

Mathematics

1 answer:

Step2247 [10]3 years ago

7 0

Answer: H

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What is the value of x? 103√ 10 53√ 5

d1i1m1o1n [39]

Sin 60⁰= x/10
x=10*sin 60⁰
x=10*(√3/2)=5√3
x=5√3
Answer is x=5√3.

8 0

3 years ago

Read 2 more answers

Look at image for question please

pickupchik [31]

Answer:

below

Step-by-step explanation:

mean=EFX÷N

=40÷8

THIS IS THE MEAN OF GIVEN DATA.

3 0

3 years ago

Give the domain and range.

3241004551 [841]

Answer:

The correct answer is a.

Step-by-step explanation:

The domain is the plotted points on the x-axis.

The range is the plotted points on the y-axis.

(-3, 3), (0, 0), (2, -2)

Domain {-3, 0, 2}; Range: {3, 0, -2}

8 0

3 years ago

Read 2 more answers

Helpppppp pllzzzzzzzzz

fgiga [73]

Answer:

The length of side of largest square is 15 inches

Step-by-step explanation:

The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.

Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.

So,

Area of square 1: 81 square inches

$s^2 = A\\s^2 = 81\\\sqrt{s^2} = \sqrt{81}\\s = 9$

Perimeter of square 2: 48 inches

$4*side = P\\4* side = 48\\side = \frac{48}{4}\\side = 12\ inches$

We can see that a right angled triangle is formed.

Here

Base = 12 inches

Perpendicular = 9 inches

And the side of largest square will be hypotenuse.

Pythagoras theorem can be used to find the length.

$(H)^2 = (P)^2+(B)^2\\H^2 = (9)^2+(12)^2\\H^2 = 81+144\\H^2 = 225\\\sqrt{H^2} = \sqrt{225}\\H = 15$

Hence,

The length of side of largest square is 15 inches

5 0

3 years ago

What is the simplified form of the following expression?

kogti [31]

Answer:

$\sqrt{3}$

Step-by-step explanation:

We will be using 2 properties of radicals in this simplification (outlined below).

$\sqrt{a*b}=\sqrt{a}* \sqrt{b}$
$\sqrt{a}*\sqrt{a}=a$

Let's simplify this:

$2\sqrt{27} +\sqrt{12} -3\sqrt{3}-2\sqrt{12}\\ =2\sqrt{9*3}+\sqrt{4*3} -3\sqrt{3}-2\sqrt{4*3} \\=2\sqrt{9} \sqrt{3} +\sqrt{4} \sqrt{3}-3\sqrt{3}-2\sqrt{4} \sqrt{3} \\=2(3)\sqrt{3}+(2)\sqrt{3} -3\sqrt{3}-2(2)\sqrt{3} \\ =6\sqrt{3} +2\sqrt{3}-3\sqrt{3}-4\sqrt{3} \\=\sqrt{3}$

First answer choice is right.

5 0

3 years ago