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Rama09 [41]
2 years ago
5

Is ABD = CDB?? Justify the answer I will mark the brainiest :))

Mathematics
2 answers:
mel-nik [20]2 years ago
3 0
Yes ABD=CBD since they both are just half of the triangle
vlabodo [156]2 years ago
3 0

Step-by-step explanation:

it is given, AD=DC (S),

:. <DAB=<DCB (A) isosceles triangle,

and, <ADB=<CDB (A) BD bisector of <D.

So, by A-S-A criterion we can prove that triangle ( give it in sign) ABD = triangle ( give it in sign) CBD.

Hence, we can say that <ABD is not equal to <CDB.

Hope this helps you.

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3 years ago
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IgorC [24]

Answer: Choice C

\begin{array}{|c|c|} \cline{1-2}x & y\\\cline{1-2}0 & 1\\\cline{1-2}2 & 2\\\cline{1-2}4 & 3\\\cline{1-2}6 & 4\\\cline{1-2}\end{array}

=========================================================

Explanation:

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Each point is of the form (x,y)

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Each of these points is then listed in the table format as shown above.

There are infinitely many other points on the line; however, we only select a few of them to make the table (or else we'd be here all day).

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8 0
2 years ago
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tatiyna

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2 years ago
What is the value of b?
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62° is the answer. Just add 26 and 36.
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3 years ago
Find f(6) if f(x)=x^2 divided by 3x+x
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So, if I'm understanding you correctly, f(x)=x^2 divided by 3x+x, or
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3 0
3 years ago
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