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Rama09 [41]
2 years ago
5

Is ABD = CDB?? Justify the answer I will mark the brainiest :))

Mathematics
2 answers:
mel-nik [20]2 years ago
3 0
Yes ABD=CBD since they both are just half of the triangle
vlabodo [156]2 years ago
3 0

Step-by-step explanation:

it is given, AD=DC (S),

:. <DAB=<DCB (A) isosceles triangle,

and, <ADB=<CDB (A) BD bisector of <D.

So, by A-S-A criterion we can prove that triangle ( give it in sign) ABD = triangle ( give it in sign) CBD.

Hence, we can say that <ABD is not equal to <CDB.

Hope this helps you.

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What is the electoral college? select one:
ad-work [718]

The answer is "electors from each state who cast ballots for president and vice president."

Have a great night! :)

8 0
3 years ago
Charlie is watching hot air balloons. balloon a has risen at a 50° angle. balloon b has risen at a 78° angle. if the distance fr
AfilCa [17]

The distance from Balloon A to Balloon B, d ≈ 1,052 feet

What is distance ?

  • Distance is defined to be the magnitude or size of displacement between two positions.
  • Note that the distance between two positions is not the same as the distance traveled between them.
  • Distance traveled is the total length of the path traveled between two positions. Distance traveled is not a vector.

The given parameters are;

The angle at which Balloon A rises, x° = 50° above horizontal

The angle at which Balloon B rises, y° = 78° above horizontal

The (vertical) distance of Balloon A to the ground, h = 1,000 ft.

The required parameter;

The distance from Balloon A to Balloon B, d

We find the distances of the balloons from Charlie and the angle between the balloon strings, θ, then apply cosine rule

Let,

The height of the balloon strings are equal

The distance of Balloon A to the ground, h₁ = The distance of Balloon B to the ground, h₂ = 1,000 ft.

The distance of the Balloon A  from Charlie, l₁, is given as follows;

l₁ × sin(x°) = h₁

∴ l₁ = h₁/(sin(x°))

Which gives;

l₁ = 1,000 ft./(sin(50°)) ≈ 1,305.41 ft.

l₁ ≈ 1,305.41 ft.

For Balloon B, we get;

h₁ = h₂ = 1,000 ft.

∴ l₂ = 1,000 ft./(sin(78°)) ≈ 1,022.34 ft.

l₂ ≈ 1,022.34 ft

The angle between the balloon strings, θ = 180° - (x° + y°)

∴ θ = 180° - (50° + 78°) = 52°

The angle between the balloon strings, θ = 52°

By cosine rule, we have;

d = √(l₁² + l₂² - 2 × l₁ × l₂ × cos(θ))

∴ d = √(1,305.41² + 1,022.34² - 2 × 1,305.41×1,022.34 × cos(52°)) ≈ 1,052 feet

Therefore, the distance from Balloon A to Balloon B, d ≈ 1,052 feet

Learn more about distance

brainly.com/question/15172156

#SPJ4

7 0
2 years ago
Here are the LETTERS that goes with the file<br> <br> A=3<br> B=4<br> C=6<br> D=2
Jlenok [28]

Answer:

I think 120

Step-by-step explanation:

8 0
3 years ago
Need help on this question
stellarik [79]

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3 0
3 years ago
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Rewrite the equation y−2=−3/2(x+6) in standard form.
navik [9.2K]

For this case we have that by definition, the standard form of the equation of the line is given by:

ax + by = c

We have the following equation:

y-2 = - \frac {3} {2} (x + 6)

We manipulate the equation algebraically:

y-2 = - \frac {3} {2} x- \frac {3 * 6} {2}\\y-2 = - \frac {3} {2} x \frac {18} {2}\\y-2 = - \frac {3} {2} x-9\\y-2 + 9 = - \frac {3} {2} x\\y-7 = - \frac {3} {2} x\\2 (y-7) = - 3x\\2y-14 = -3x\\3x + 2y = 14

Finally, the equation is:

3x + 2y = 14

Answer:

3x + 2y = 14

3 0
3 years ago
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