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vova2212 [387]
3 years ago
14

. Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end behavior and pro

vide the leading term.
-3x5 + 9x4 + 5x3 + 3
Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0
-15+36+15+3=

-15+15=0=

36+ 3=

39
Nutka1998 [239]3 years ago
6 0

Answer:

The end behaviour of this function is -ꝏ when x approaches +ꝏ and +ꝏ when x approaches -ꝏ. The leading term is -3x^5.

Step-by-step explanation:

The end behaviour can be found by taking the limits of function for x approaching +ꝏ and -ꝏ:

lim x→+/-ꝏ (-3x^5+9x^4+5x^3+3)  

To solve the limits it must be factorized the highest term in the polynomial:

lim x→+/-ꝏ {-3x^5*[-3x^5/(-3x^5)+9x^4/(-3x^5)+5x^3/(-3x^5)+3/(-3x^5)]}

By simplifying:

lim x→+/-ꝏ {-3x^5*[1-3/x-5/3x^2-1/x^5)]}

If we first take the limits in the within the square brackets, we will notice than whether the limits approaches +ꝏ or -ꝏ the limits of each of these terms tend to zero due to the denominator is greater than the numerator:

lim x→+/-ꝏ {-3x^5*[1-0-0-0)]}

lim x→+/-ꝏ {-3x^5*[1]}

lim x→+/-ꝏ {-3x^5}

This way we find the leading term. Now taking the positive and negative limits:

lim x→+ꝏ {-3x^5} = -ꝏ

and:

lim x→-ꝏ {-3x^5} = +ꝏ

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Define each following sets by listing its elements, the set of letters in the word "salt"
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<h3>What is set?</h3>

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We have given letter:

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Here, no letter is repeated.

So we can write it as roaster form:

Let's denote the set as S

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brainly.com/question/8053622

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8 0
2 years ago
9.21 <br><img src="https://tex.z-dn.net/?f=9.21%20%5Cdiv%200.4%20%3D%20" id="TexFormula1" title="9.21 \div 0.4 = " alt="9.21 \di
Whitepunk [10]
Let us do it by converting the 0.4 to a fraction, it has one decimal, so we'll use one zero at the denominator.

and 9.21 to a fraction as well, two decimals, thus two zeros at the denominator then,

\bf 9.21\div 0.4\\\\&#10;-------------------------------\\\\&#10;0.\underline{4}\implies \cfrac{04}{1\underline{0}}\implies \cfrac{4}{10}\implies \cfrac{2}{5}\qquad \qquad \qquad \qquad 9.\underline{21}\implies \cfrac{921}{1\underline{00}}\\\\&#10;-------------------------------\\\\&#10;9.21\div 0.4\implies \cfrac{921}{100}\div \cfrac{2}{5}\implies \cfrac{921}{100}\cdot \cfrac{5}{2}\implies \cfrac{921}{20}\cdot \cfrac{1}{2}\implies \cfrac{921}{40}&#10;\\\\\\&#10;23\frac{1}{40}\implies 23.025
3 0
3 years ago
Step by step on how to do this plz
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6 0
3 years ago
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