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AlekseyPX
2 years ago
12

Can someone help me with this math homework please!

Mathematics
2 answers:
azamat2 years ago
7 0

It is not necessary that the function decreasing over a given interval always be negative.

A function f(x) (value) decreases as x increases.

This does not mean that value of f(x) is negative.

It can have positive number as range.

Arlecino [84]2 years ago
5 0

Answer:

No

Explanation:

Firstly, observe the function f(x)=-2^x, this function is decreasing and negative (below the x-axis) over its domain.

At the same time, consider the function h(x)=1-x² over the interval 0 ≤ x≤1. this function is decreasing over the said interval. However, it is not negative.

Therefore, a function doesn´t need to be negative over the interval it is decreasing on.

<u>------------------------</u>

Hope it helps...

Have a great day!!

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Fatima wants to find the value of sine theta, given cotangent theta = four-sevenths. which identity would be best for fatima to
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By using trigonometric relations, we will find that:

sin(θ) = (√33)/7 = √(33/49)

<h3>How to find the value of the sine?</h3>

Remember that for a right triangle, we have the relations:

cos(a) = (adjacent cathetus)/(hypotenuse)

sin(a) = (opposite cathetus)/(hypotenuse).

Here we know that:

cos(θ) = 4/7

Then we can say that we have a triangle with an adjacent cathetus of 4 units and a hypotenuse of 7 units. Now we need to find the other cathetus.

opposite cathetus = √(7^2 - 4^2) = √33

Then we can write:

sin(θ) = (√33)/7 = √(33/49)

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3 0
2 years ago
For math Equations what is 4x + 5 = x + 8??
vfiekz [6]

Answer:

x = 1

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4x + 5 = x + 8

4x = x + 3 --- subtract 5 from both sides

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3 0
3 years ago
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What equation represents the line that passes through the points (-3 7 and (3 3?
dexar [7]


<span>Hello : let  A(-3,7)    B(3,3)
the slope is :   (YB - YA)/(XB -XA)
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y = (-2/3)x +b

 

the line through point B (3,3) :  3 = (-2/3)(3)+b<span>
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3 years ago
(08.03)A set of equations is given below:
cricket20 [7]

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A

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3 years ago
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<img src="https://tex.z-dn.net/?f=solve%20for%20%22m%22%20t%3D%5Cfrac%7Bms%7D%7Bm%2Bn%7D" id="TexFormula1" title="solve for &quo
dalvyx [7]

Answer:

\boxed{\sf \ \ \ m = -\dfrac{tn}{t-s} \ \ \ }

Step-by-step explanation:

Hello,

let s assume that m+n is different from 0

we have this equation and we need to find m as a function of t, s, and n

t=\dfrac{ms}{m+n}

<=>

(m+n)*t=ms\\\\ tm+tn=sm\\ (t-s)m = -tn\\ m = -\dfrac{tn}{t-s}

for t-s different from 0, so t different from s

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3 years ago
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