What is the gcf of 96^5 and64^2

Solve the system by substitution y=4 2x+3y=-20

Anna35 [415]

The answer to the question

5 0

3 years ago

Solve for x 6X +7 equals 25

Dimas [21]

Answer:

x = 3

Step-by-step explanation: 6x + 7 = 25

The first thing that you want to do is take away 7 from both sides. 7-25=18

The equation that is left is, 6x=18 Now you have to get X away from 6, you divided 6x/6 and 18/6 which leaves you with x=3

5 0

3 years ago

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Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab

Sphinxa [80]

Answer: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

$\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5$

Using the poisson process, we get that

(a) less than or equal to 12

probability= $P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980$

(b) equal to 13

probability= $P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013$

(c) greater than 12

probability= $P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020$

(d) equal to 20

probability= $P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026$

(e) between 10 and 15, inclusively

probability= $P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318$

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0

3 years ago

Multiply the polynomial (x+3)(x+4) A)x^2+7 B)x^2+12 C)x^2+7x+12

LekaFEV [45]

Your answer is option C: x^2+7x+12

3 0

3 years ago

Write 9.4*10^7 a. in standard notation b. write out the name of this number

Vitek1552 [10]

Answer:

a. 94,000,000

b. Ninety-four million

Step-by-step explanation:

In order to find this number, move the decimal place to the right by the number in the exponent. Since the exponent is 7, we move it to the right of the 4 (that's one move), then we have six more moves. So we add six zeroes to the end of the number.

94,000,000

5 0

4 years ago