When solving system equations, we can use substitution method or elimination. Today I'm using substitution method.
First name the 2 equations.
3x + y = 3 (1)
x + y = 2 (2)
Now pick one equation and express one algebra in forms of the other.
From (2),
x = 2 - y (3)
Now substitute (3) into (1),
3(2-y) + y = 3
6 - 3y + y = 3
6 - 2y = 3
6 - 3 = 2y
y = 1.5
Now substitute y = 1.5 into (2)
x + 1. 5 = 2
x = 2 - 1.5
x = 0.5
Therefore the answer is x = 0.5 and y = 1.5
Step-by-step explanation:
<h2>
<em>y = ± 5⁄2 x</em></h2><h2>
<em>y = ± 5⁄2 xThe equation is the left half of the hyperbola. The domain is ( – ∞, – 1⁄5 ]. The range is ( – ∞, ∞ ). The vertical line test indicates that this is not the graph of a function.</em></h2>
From 2.56 to 3.18; 3.18-2.56=0.62 increased
so if 2.56 represented 100%
0.62 represents ? %
cross multiply
?%= 0.62·100/2.56=24.21875 which rounded to the nearest whole is 24%
Answer is B).
