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wolverine [178]
3 years ago
13

3 7 11 15 19 Find the 9th term in the sequence.

Mathematics
1 answer:
Allushta [10]3 years ago
5 0
3
7
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51
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Sue purchased a $30,000 life insurance policy at the price of $24 for each $1000 of coverage. If she pays the premium in 12 mont
Inessa [10]

Cost of life insurance is $30000 at a price of for each $24 for each $1000 of coverage.

Cost = \frac{24}{1000}\times30000

= $720

Premium is paid each month then it becomes \frac{720}{12}=60

=$60

3 0
3 years ago
A middle school band has 45 sixth and seventh graders The ratio of sixth to seventh graders is 2 to 3 how many sixth graders are
AnnyKZ [126]

Answer:

  18

Step-by-step explanation:

There are 2+3 = 5 ratio units representing 45 band members, so each ratio unit represents 45/5 = 9 band members.

The 2 ratio units of sixth graders represent 2×9 = 18 sixth grade band members.

5 0
3 years ago
If a line has a slope of -8/9 a line that is perpendicular has a slope of what​
miss Akunina [59]
9/8

Explanation: a perpendicular slope is the opposite of what the normal slope was before
5 0
3 years ago
4x-3y=2<br> 3x=5y=16<br> solve using substitution method
vodomira [7]

\left\{\begin{array}{ccc}4x-3y=2&|\text{add 3y to both sides}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}4x=3y+2&|\text{divide both sides by 4}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}x=0.75y+0.5&(*)\\3x+5y=16\end{array}\right\\\\\text{substitute}\ (*)\ \text{to the second equation}\\\\3(0.75y+0.5)+5y=16\qquad\text{use distributive property}\\\\(3)(0.75x)+(3)(0.5)+5y=16\\\\2.25y+1.5+5y=16\qquad\text{subtract 1.5 from both sides}\\\\7.25y=14.5\qquad\text{divide both sides by 7.25}

\boxed{y=2}\\\\\text{substitute the value of y to}\ (*):\\\\x=0.75(2)+0.5\\\\x=1.5+0.5\\\\\boxed{x=2}\\\\Answer:\ x=2\ and\ y=2\to(2,\ 2)

7 0
3 years ago
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals
andrew11 [14]

Answer:

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.

8 0
3 years ago
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