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jeyben [28]
4 years ago
11

The perimeter of a rectangle is 141 feet, and the length is twice the width. What are the dimensions ?

Mathematics
2 answers:
raketka [301]4 years ago
8 0

Answer:

The width is 23.5 ft and the length is 47 ft

Step-by-step explanation:

The perimeter of a rectangle is given by

P = 2(l+w)

141 = 2(l+w)

The length is twice the width

l = 2w

141 = 2 ( 2w+w)

141 = 2( 3w)

141 = 6w

Divide each side by 6

141/6 = 6w/6

23.5 = w

l = 2w = 2(23.5) = 47

The width is 23.5 ft and the length is 47 ft

Elanso [62]4 years ago
4 0

Answer:

\boxed{Width = 23.5 \ feet}

\boxed{Length = 47 \ feet}

Step-by-step explanation:

Let Length be l and Width be w

Perimeter = 2(Length) + 2(Width)

<u><em>Condition # 1:</em></u>

2l+2w = P

=> 2 l + 2 w = 141

<u><em>Condition # 2:</em></u>

=> l = 2w

Putting the second equation in the first one

=> 2(2w)+2w = 141

=> 4w + 2w = 141

=> 6w = 141

Dividing both sides by 6

=> Width = 23.5 feet

Given that

=> l = 2w

=> l = 2(23.5)

=> Length = 47 feet

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