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raketka [301]
3 years ago
8

Which statement is true about the solution if the equation 3y + 4 = -2?

Mathematics
1 answer:
frez [133]3 years ago
4 0

B. It had 1 solution
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If $860 is invested for one year at 11% simple interest, how much interest is earned?
Licemer1 [7]
860 *11/100=9460/100=94.6
94.6 is earned

4 0
3 years ago
Which table represents a linear function?
Vesna [10]
There are no pictures or tables
3 0
3 years ago
Read 2 more answers
Find the center of the circle that you can circumscribe about ABC A=(-1,-2) B=(-5,-2) C=(-1,-7)
Luda [366]

Answer:

O : (-3,-4.5)

Step-by-step explanation:

center of circle: O (x.y)

Radius (r) = OA = OB = OC

r² = (x - (-1))² + (y - (-2))² ---- OA²  

r² = (x - (-5))² + (y - (-2))² ---- OB²

r² = (x - (-1))² + (y - (-7))² ---- OC²

OA²=OB² : (x - (-1))² + (y - (-2))² =  (x - (-5))² + (y - (-2))²

(x+1)² - (x+5)² = 0       x²+2x+1-x²-10x-25 = 0

8x = -24

x = -3

OA² = OC²   (x - (-1))² + (y - (-2))² = (x - (-1))² + (y - (-7))²

y²+4y+4 = y² +14y +49

10y = -45

y = - 4.5

O : (-3,-4.5)

6 0
4 years ago
The student council is making corsages to sell at prom. They spent $350 on materials such as
erma4kov [3.2K]

Answer:

The inequality 7.50c - 350 ≥ 700 can be used.

Step-by-step explanation:

Given that:

Amount spent on materials = $350

Amount the council needs to earn = $700

Selling price per corsage = $7.50

Number of corsages sold = c

Selling price per corsage * Number of corsages sold - amount spent on materials ≥ amount needs to be earned

7.50c - 350 \geq 700

Hence,

The inequality 7.50c - 350 ≥ 700 can be used.

3 0
3 years ago
Find the standard form of the equation of the parabola with a focus at (5, 0) and a directrix at x = -5.
Elena-2011 [213]
Let's notice, the focus is at (5,0) and the directrix at x = -5.

keep in mind that there's a distance "p" from the vertex to either of those fellows, therefore, if the focus is at 5,0 and the directrix x = -5, the vertex is half-way between them, check the picture below.

notice the distance "p" there, now, is a horizontal parabola, opening to the right, meaning the value for "p" is positive, or just 5, thus

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})}
\\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}})
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=0\\
k=0\\
p=5
\end{cases}\implies (y-0)^2=4(5)(x-0)\implies y^2=20x
\\\\\\
\cfrac{y^2}{20}=x\implies \cfrac{1}{20}y^2=x

8 0
3 years ago
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