Order 7.007, 70.07, 70.700, 7.070 greatest to least.

Which expression is equivalent to 2(x+7)-18+4/5 ?

Vadim26 [7]

Answer:

4.7/5

Step-by-step explanation:

7 0

2 years ago

construct potential hypotheses or research questions to relate the variables in each of the following examples. also, write a br

Alexxx [7]

Construct potential hypotheses or research questions to relate the variables in each of the following examples -

Political party and support of the affordable care act -

Given this, there can be a relationship between the ideological group and the support of the moderate consideration act.
that various ideological groups may support various types of government disability conspiracies and might have various goals.
A few gatherings might focus on a list of topics or problems and might provide serious thought at some random time.
which might facilitate the implementation of the Affordable Care Act, while others would be gradually forgiving toward such arrangements.
The implementation and success of the Affordable Care Act may depend on the rise of certain ideological movements.

and their ability to express what they think about the Act's purpose.

Learn more about hypotheses

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3 0

2 years ago

In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the

earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

A = video components need repair within 1 year

B = electronic components need repair within 1 year

C = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events A, B and C are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

$=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278$

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

$=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277$