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Gennadij [26K]
3 years ago
14

a rectangular block is such that the sides of its base are of the length x cm and 3x cm. The sum of all the lengths of all its e

dges is 20cm. Find the volume.
Mathematics
1 answer:
Xelga [282]3 years ago
5 0

Answer:

15x^2 - 12x^3

Step-by-step explanation:

A rectangular block has 3 parts that play into its volume.  length, width and height.  The question gives us length and width in the form of x and 3x, so height is what's missing.

It gives us a bit more information saying the sum of its edges is 20.  We also have to ask how many lengths, widths and heights are there.  That may be a bit hard to understand, but  is you are looking at a block I could ask how many edges are vertical, just going up and down.  These would be the heights.  There are 4 total, and this goes the same for length and width, so 4*length + 4*width and 4*height = 20.  

Taking that and plugging in x for length and 3x for width (or you could do it the other way around, it doesn't matter, you get:

4*x + 4*3x + 4*height = 20

4x + 12x + 4h = 20

16x + 4h = 20

4h = 20 - 16x

h = 5 - 4x

Now we have h in terms of x, which lets us easily find the volume just knowing x.  To find the volume of a rectangular block you just multiply the length, width and height.

x*3x*(5-4x)

3x^2(5-4x)

15x^2 - 12x^3

Question doesn't give a specific value for x at all so you should be done there.  Any number you plug in for x should get you the right answer

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Solve for:<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%205x%20%3D%201" id="TexFormula1" title="x^{2} + 5x = 1
mixer [17]

x^2+5x-1=0\\x^2+5x+(\frac{5}{2})^2-(\frac{5}{2})^2-1=0\\(x+\frac{5}{2})^2-\frac{25}{4}-\frac{4}{4}=0\\(x+\frac{5}{2})^2-\frac{29}{4}=0\\(x+\frac{5}{2})^2=\frac{29}{4}\\x+\frac{5}{2}=\sqrt{\frac{29}{4}} , x+\frac{5}{2}=-\sqrt{\frac{29}{4}}\\x=\frac{\sqrt{29} }{2} - \frac{5}{2} , x=-\frac{\sqrt{29} }{2} - \frac{5}{2} \\x=\frac{\sqrt{29}-5 }{2} , x=-\frac{\sqrt{29} -5}{2}

4 0
3 years ago
Can someone explain this
horsena [70]

9514 1404 393

Answer:

  • resultant force: 93.946∠-10.62° N
  • line of action: 17.314x +92.337y = 809.433

Step-by-step explanation:

We can use the notation a∠b to represent the (x, y) components (a·cos(b), a·sin(b)), where angle b is measured CCW from the +x direction. If we label the forces a, b, c, d clockwise from A, then we have ...

  a = 80∠0° = (80, 0)

  b = 60∠90° = (0, 60)

  c = 90∠45° = (63.640, 63.640)

  d = 150∠-110° = (-51.303, -140.954)

__

If we label point A the origin, then the clockwise torque on point A is the sum of products of the force x-component and its y location, and its y-component and the negative of its x location.

  T = (0, 0)·(80, 0) +(3, 0)·(0, 60) +(3, -8)·(63.640, 63.640) +(0, -8)·(-51.303, -140.954)

  T = 809.433 . . . . n·m, the CW torque on point A

__

The sum of forces is ...

  F = a +b +c +d = (92.337, -17.314) = 93.946∠-10.62° . . . N

__

This force, applied to the point of application, must generate the same torque as the given forces. That is ...

  F·(y, -x) = 809.433

Then the equation of the line of action is ...

  17.314x +92.337y = 809.433 . . . . . x and y in meters measured from A

Any point (x, y) on this line will serve as a point of application of the force. Unfortunately, this line of action does not pass through the rectangular plate. The attachment shows the point (D) on the line of action that is closest to point A.

_____

<em>Additional comment</em>

The resultant force could be decomposed into two forces acting <em>on the rectangular plate</em>. One could be of much larger magnitude, operating at the corner opposite point A. This force would provide the necessary torque. Another would be acting on point A, providing no torque, but with components such that the resultant has the correct magnitude and direction.

6 0
3 years ago
Evaluate C(44,21) use scientific notation, round to 3 decimal places as needed.
STALIN [3.7K]
C(44,21)=\dfrac{44!}{21!23!}=\dfrac{24\cdot25\cdot\ldots\cdot43\cdot44}{2\cdot3\cdot\ldots\cdot 20\cdot21}=2,012,616,400,080\\&#10;\approx2.013\cdot10^{12}
6 0
3 years ago
Which transformation is a translation?
astra-53 [7]

Answer:

[2] Translation

[4]Transformation

Step-by-step explanation:

Translation is just moving the shape.

Transformation is changing the shape and tilting it changed the shape.

7 0
3 years ago
To find 10, Beau found 32 = 9 and 42 = 16. He said that since 10 is between 9 and 16, 10 is between 3
AlexFokin [52]

Given that:

Consider it is \sqrt{10} instead of 10 on two places.

\sqrt{10} is between 3  and 4. So, Beau thinks a good estimate for \sqrt{10} is = 3.5.

Solution:

To find \sqrt{10}, Beau found 3² = 9 and 4² = 16.

He said that since 10 is between 9 and 16.

Since 10 is close to 9, therefore \sqrt{10} must be close to 3. So, Beau's estimate is high.

Now,

(3.1)^2=9.61

(3.2)^2=10.24

Since, 10 lies between 9.61 and 10.24, therefore \sqrt{10} must be lies between 3.1 and 3.2.

\dfrac{3.1+3.2}{2}=3.15

Therefore, the estimated value of \sqrt{10} is 3.15.

4 0
3 years ago
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