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marishachu [46]
3 years ago
13

The first one asks for the value of x. I need help on both. I am struggling to understand how to do this, please help

Mathematics
1 answer:
zzz [600]3 years ago
6 0

(1) since the horizontal lines are parallel, and you know the vertical intersecting line crosses at right angle, it must be that the two angles with variable x sum up to 90 degrees. So same rewritten as an equation:

x+8+6x-58 = 90

7x = 140

x = 20 (degrees)

(2) here you have two variable so you will need to find two equations.

The first one comes from the triangle and its angles summing up to 180:

63 + (3x+45) + (y-6) = 180

The second one comes from the fact that the two horizontal lines are parallel and so the angles (7x-7) and (3x+45) must be the same:

7x-7=3x+45

Let's solve the last one first:

4x = 52

x = 13

then plug this solution into the first equation and solve for y

63 + (3x+45) + (y-6) = 180

3x + y = 78

y = 78-39 = 39

so the value of y is 39 (degrees)

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Let's say our first integer is "a".

how to get the next consecutive EVEN integer?  well, just add or subtract 2 from it, therefore, the second consecutive integer will be "a + 2".

and the next after that, will then be (a + 2) + 2, or "a + 4".

so those are are 3 integers, a           a + 2           a+4

notice that, from any even or odd integer, if you hop twice either forwards or backwards, you'll land on another even or odd integer respectively.

2 + 2 is 4, or 8 + 2 is 10  some even ones

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\bf \stackrel{\textit{3 times the first}}{3a}~~=~~\stackrel{\textit{26 less than twice the sum of the others}}{2[~(a+2)+(a+4)~]~~~-26}
\\\\\\
3a=2[~2a+6~]-26\implies 3a=4a+12-26\implies 3a=4a-14
\\\\\\
0=a-14\implies 14=a

what are the other two consecutive integers?  well, a + 2 and a + 4.
4 0
3 years ago
Y=x-4 y=4x+2<br> whats the solution of system equations
Fittoniya [83]

Answer:

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Step-by-step explanation:

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Making x the subject then

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Subsrituting the value of x into any of the initial equations

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Therefore, the solution is

X=-2

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Answer:

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Answer: 4.4

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