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3 years ago

Please help me f(x) =3x^2 + 2x - 1 what is f(5)

Mathematics

2 answers:

Sergio039 [100]3 years ago

6 0

Answer:

Step-by-step explanation:

f(5)=3(5)+2. f(5)=17

damaskus [11]3 years ago

4 0

Answer:

Step-by-step explanation:

f(x) =3x^2 + 2x - 1

what is f(5)

f(5) = 3(5)² + 2(5) - 1

f(5) = 75 + 10 - 1

f(5) = 84

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I need help with this

zloy xaker [14]

A) The formula for Scale factor:
Size of the image/ size of the object

6/24 = 1/4

b) Value of x
8 / 1/4 = 32

c)Value of y
36 *1/4= 9

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3 years ago

What is the median of the data set?

LUCKY_DIMON [66]

The median is the middle number

= 36

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3 years ago

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If s(x)=x-7 and t(x)=4x^2-x+3 which expression is equivalent to (txs)(x)?

gogolik [260]

For this case we have by definition that:

$(f * g) (x) = f (x) * g (x)$

In this case we must find $(t * s) (x),$ so:

( $(t * s) (x) = t (x) * s (x) = (4x ^ 2-x + 3) * (x-7) =$

We must apply distributive property that states that:

$(a + b) (c + d) = ac + ad + bc + bd$

So:

$(4x ^ 2-x + 3) * (x-7) = 4x ^ 3-28x ^ 2-x ^ 2 + 7x + 3x-21 = 4x ^ 3-29x ^ 2 + 10x-21$

Answer:

$4x^3-29x^2+10x-21$

7 0

3 years ago

(pls help!! my teacher whats me to pass this) for the point S(-3, 3), where will the image of this point be located after applyi

IceJOKER [234]

Answer: (0, 0)

Step-by-step explanation:

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4 0

2 years ago

Read 2 more answers

Find (f ∘ g)(-6) when f(x) = 9x + 2 and g(x) = -9x2 - 2x + 1.

Salsk061 [2.6K]

Given that the two functions are $f(x)=9x+2$ and $g(x)=-9x^2-2x+1$

We need to determine the value of $(f \circ g)(-6)$

<u>The value of </u> $(f \circ g)(x)$ <u>:</u>

The value of $(f \circ g)(x)$ can be determined using the formula,

$(f \circ g)(x)=f[g(x)]$

Substituting $g(x)=-9x^2-2x+1$ in the above formula, we get;

$(f \circ g)(x)=f[-9x^2-2x+1]$

Now, substituting $x=-9 x^{2}-2 x+1$ in the function $f(x)=9x+2$ , we get;

$(f \circ g)(x)=9(-9x^2-2x+1)+2$

$(f \circ g)(x)=-81x^2-18x+9+2$

$(f \circ g)(x)=-81x^2-18x+11$

Thus, the value of $(f \circ g)(x)$ is $(f \circ g)(x)=-81x^2-18x+11$

<u>The value of </u> $(f \circ g)(-6)$ <u>:</u>

The value of $(f \circ g)(-6)$ can be determined by substituting x = -6 in the function $(f \circ g)(x)=-81x^2-18x+11$

Thus, we have;

$(f \circ g)(-6)=-81(-6)^2-18(-6)+11$

$(f \circ g)(-6)=-81(36)-18(-6)+11$

$(f \circ g)(-6)=-2916+108+11$

$(f \circ g)(-6)=-2797$

Thus, the value of $(f \circ g)(-6)$ is -2797

Hence, Option B is the correct answer.

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4 years ago