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Dahasolnce [82]
2 years ago
5

A cube that has side lengths measuring 7 inches?

Mathematics
1 answer:
Marianna [84]2 years ago
8 0
I don't know the exact question but heres the best i got
the surface area would be 294 inches
one face would be 49 inches
and the volume would be 343
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Seattle, WA and San Francisco, CA lie on the same longitudinal line. San Francisco is at 38° latitude and Seattle is at 47° lati
Helen [10]

Step 1.

Calculate measure of angle α:

47^o-38^o=9^o

Step 2.

Calculate what fraction of the angle 360° ​​is the angle α:

\dfrac{9^o}{360^o}=\dfrac{1}{40}

Step 3.

Calculate the circumference of the Earth (circle):

C=2\pi r\to C=2\pi\cdot4000=8000\pi\ mi

Step 4.

The length of arc is equal 1/40 of the circumference:

\dfrac{1}{40}C=\dfrac{1}{40}\cdot8000\pi=200\pi\ mi

\pi\approx3.14\to\dfrac{1}{40}C\approx200\cdot3.14=628\ mi


<h3>Answer: A) 628 miles</h3>

7 0
3 years ago
What is the result when the number 15 is decreased by 6%?
Tasya [4]

Answer:

It would be 14.1

Step-by-step explanation:

6% of 14 is 0.9, so subtracting that from 15 would leave you with 14.1

6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
2 years ago
How to find standard deviation from true probability and sample size.
bixtya [17]

Answer:

I can even see anything can you reupload your answer, please?

Step-by-step explanation:

8 0
2 years ago
Round 2,641 to the nearest thousand. Round 2,641 to the nearest thousand?
Elenna [48]

Answer:

2641

we round off 2

then we get,

2641=3000

8 0
3 years ago
Read 2 more answers
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