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dexar [7]
3 years ago
10

According to Euclidean geometry, a plane contains at least

Mathematics
1 answer:
Burka [1]3 years ago
3 0

Answer:

ok

Step-by-step explanation:

wheres the rest

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2/3 divided by 3 halppppopp
Kitty [74]
The answer is 2/9 in lowest terms.

In decimal form its 0.222222
7 0
3 years ago
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Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
Find the coordinates of d if e is the midpoint of CD for C(-3, 4) and E(0, 1).
Yanka [14]

Answer:

D(3;-2).

Step-by-step explanation:

1)  X_D=2*X_E-X_C;\\Y_D=2*Y_E-X_C.

2) according to the formulas above:

X_D=2*0+3=3;\\Y_D=2*1-4=-2.

3) finally, D(3;-2).

8 0
3 years ago
What is the factored form of this expression?
Naddika [18.5K]

Answer:

(x+9)(x-9)

Step-by-step explanation:

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The coordinates of the vertices of a rectangle are (–2, 3), (4, 3), (4, –4), and (–2, –4). What are the dimensions of the rectan
Paladinen [302]
Find distance of side = (y₂- y₁) / (x₂- x₁)
 
you can get length and width  
then area = length * width
perimeter = 2 * (length + width) 
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