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agasfer [191]
3 years ago
6

lass="latex-formula">
Mathematics
1 answer:
kipiarov [429]3 years ago
7 0

Answer:

x = y/5 + 6/5

Step-by-step explanation:

Solve for x:

5 x - y = 6

Add y to both sides:

5 x = y + 6

Divide both sides by 5:

Answer:  x = y/5 + 6/5

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Ron walks 0.5 miles on track in 10 minutes Stevie was 0.25 mile on the track in6 minutes find the unit rate for each walker in m
Leya [2.2K]

Answer:

Ron is the faster walker ; Ron = 3mph |  Stacie = 2.5mph

Step-by-step explanation:

To find per hour it is easy since both are factors of 60

(0.5*6)/(10*6) = 3mph

(0.25*10)/(6*10) = 2.5mph


5 0
3 years ago
Jon recently drove to visit his parents who live 270 270 miles away. On his way there his average speed was 24 24 miles per hour
Ber [7]

Answer:

He drove there at 60 mph, and he drove back at 36 mph.

Step-by-step explanation:

one way distance = d = 270 miles

average speed on way back = s

average speed on the way there = s + 24

time driving there = t

time driving back = 12 - t

average speed = distance/time

distance = speed * time

going there:

270 = (s + 24)t

270 = st + 24t

going back

270 = s(12 - t)

270 = 12s - st

We have a system of equations:

270 = st + 24t

270 = 12s - st

Solve the first equation for t.

t(s + 24) = 270

t = 270/(s + 24)

Substitute in the second equation.

270 = 12s - s[270/(s + 24)]

270 = 12s - 270s/(s + 24)

Multiply both sides by s + 24.

270s + 6480 = 12s^2 + 288s - 270s

12s^2 - 252s - 6480 = 0

Divide both sides by 12.

s^2 - 21s - 540 = 0

(s - 36)(s + 15) = 0

s = 36 or s = -15

The average speed cannot be negative, so we discard the solution s = -15.

s = 36

s + 24 = 60

Answer: He drove there at 60 mph, and he drove back at 36 mph.

3 0
3 years ago
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enot [183]
B: -8
8 times 1 = 8, and since there is a negative in front of the 1 when you are multiplying, it should be -8/ 
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