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nignag [31]
3 years ago
5

Calculate the surface area and volume of the shape below.

Mathematics
1 answer:
pav-90 [236]3 years ago
4 0

Surface area

Let's calculate the surface area of the rectangular block. It has length, width and height of L = 15, W = 5, H = 8. The surface area is going to be

SA = 2*(LW+WH+LH)

SA = 2*(15*5+5*8+15*8)

SA = 470

This is without the cylinder attached to the top surface. If we account for that, then we'll have to subtract off the area of the circle covered up which is

pi*r^2 = pi*3^2 = 9pi = 28.27433 approximately

So 470-28.27433 = 441.72567 is the approximate surface area of the rectangular block after we subtract off the circular portion covered up by the cylinder.

----------

The lateral surface area of the cylinder is approximately

2*pi*r*h = 2*pi*3*4 = 24pi = 75.39822

Which adds onto the top circular area of 28.27433 to get 28.27433+75.39822 = 103.67255

Meaning that 103.67255 is the surface area for the cylinder portion. Again we don't worry about the bottom portion as it's not part of the outer surface.

---------

Overall, the total surface area of this compound 3D figure is

(surface area for rectangular portion) + (surface area cylinder portion) = 441.72567+103.67255 = 545.39822

When rounding to the nearest whole number, the total surface area is about 545 square cm

<h3>Answer: 545 square cm</h3>

============================================================

Volume

The rectangular block has volume L*W*H = 15*5*8 = 600 cubic cm

The cylinder has volume pi*r^2*h = pi*3^2*4 = 113.0973355 approximately

Add the two volumes to get 600+113.0973355 = 713.0973355 and this rounds to 713. We don't have to do any subtraction in this section.

<h3>Answer: 713 cubic cm</h3>
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There are 271 songs on Amy's computer. She
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A number that cannot be expressed that way is irrational. For example, one third in decimal form is 0.33333333333333 (the threes go on forever). However, one third can be express as 1 divided by 3, and since 1 and 3 are both integers, one third is a rational number.

hope it helps!

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3 years ago
If f(x) =-2+8 and g(x) = square root of x+9 which statement is true
lidiya [134]

The statement that -6 is in the domain of f(g(x)) is true

<h3>Complete question</h3>

If f(x) = -2x + 8 and g(x) = \sqrt{x + 9, which statement is true?

  • -6 is in the domain of f(g(x))
  • -6 is not in the domain of f(g(x))

<h3>How to determine the true statement?</h3>

We have:

f(x) = -2x + 8

g(x) = \sqrt{x + 9

Start by calculating the function f(g(x)) using:

f(g(x)) = -2g(x) + 8

Substitute g(x) = \sqrt{x + 9

f(g(x)) = -2\sqrt{x + 9} + 8

Set the radicand to at least 0

x + 9 \ge 0

Subtract 9 from both sides

x \ge -9

This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........

Hence, the statement that -6 is in the domain of f(g(x)) is true

Read more about domain at:

brainly.com/question/24539784

#SPJ1

3 0
1 year ago
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