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3 years ago

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" align="absmiddle" class="latex-formula">
what the simplified answer

1 answer:

DanielleElmas [232]3 years ago

8 0

Answer -
$6x - 3$
Solution:
$8x - (3 + 2x) \\ open \: the \: bracket \\8x( - \times 3)( - \times + 2x) \\8x - 3 - 2x \\ 8x - 2x - 3 \\ 6x - 3$

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The table shows a proportional relationship between x and y.

Free_Kalibri [48]

Answer:

D

Step-by-step explanation:

if y is 4 then x is -12 Because 4 times -3 is -12

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3 years ago

-5t^2+10t+22 does the ball reach a height of 35m

Alika [10]

Answer:

Step-by-step explanation:

35=-5t²+10t+22

5t²-10t+13=0

disc =b²-4ac=(-10)²-4×5×13=100-260=-160<0

t is imaginary.

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3 0

3 years ago

The largest set of x values satisfying

velikii [3]

Answer:

If $p\ge -\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

Step-by-step explanation:

Solve two inequalities for x.

1. $2,018x-p$

Separate terms with x and without x into two sides:

$2,018x-2,020x$

Multiply by -1:

$2x>-2p\\ \\x>-p$

2. $7x+3p$

Separate terms with x and without x into two sides:

$7x-10x$

Multiply by -1:

$3x>2+3p\\ \\x>\dfrac{2}{3}+p$

Find the largest set of x values satisfying both inequalities:

$x>-p\\ \\x>\dfrac{2}{3}+p$

If

$-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p$

then $x>-p$ and $mn=-p=p\cdot (-1),\ m+n=p-1.$ In this case both m and n are negative.

If $p>-\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

If $p=-\dfrac{1}{3},$ then $x>\dfrac{1}{3}$ and $mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}$

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3 years ago

How do you simplify -14/63

leonid [27]

14 = 7*2
63 = 7*9

14 7 * 2 2 2
---- = ------- 7/7 =1, so = 1 * ------ = ----
63 7 * 9 9 9

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3 years ago

Sarah has only dimes and quarters in how many different ways could she make $1.45

nignag [31]

Answer:

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Step-by-step explanation:

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3 years ago

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