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anygoal [31]
3 years ago
14

Help

" align="absmiddle" class="latex-formula">
what the simplified answer
Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0
Answer -
6x - 3
Solution:
8x - (3 + 2x) \\ open \: the \: bracket \\8x( -  \times 3)( -  \times  + 2x) \\8x  - 3 - 2x \\ 8x - 2x - 3 \\ 6x - 3
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The number of students in a chess club decreased from 18 to 12. What is the percent decrease ? Round to the nearest percent
Elena L [17]

Answer:

33.3% decrease or 33%

Step-by-step explanation: 1/3 of 18 is 6. 1/3=33.3% it moved down by six people so 33% is your answer

8 0
3 years ago
Read 2 more answers
150 - x - 2x = 120 + 2x
Svetach [21]

Answer:

x = 6

Step-by-step explanation:

Step 1: Write equation

150 - x - 2x = 120 + 2x

Step 2: Solve for <em>x</em>

  1. Combine like terms: 150 - 3x = 120 + 2x
  2. Add 3x to both sides: 150 = 120 + 5x
  3. Subtract 120 on both sides: 30 = 5x
  4. Divide both sides by 5: 6 = x
  5. Rewrite: x = 6

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

150 - 6 - 2(6) = 120 + 2(6)

144 - 12 = 120 + 12

132 = 132

5 0
3 years ago
Markus is overdrawn at the bank by $9. His brother has $15 more than him. How much money does Markus’ brother have?
shusha [124]

Answer:

24$

Step-by-step explanation:

its just 9$ + 15$ = 24$

6 0
3 years ago
Yolanda wants to complete the 50-mile biathlon in 5 hours. she gets her jogging rate up 6 miles/hour and her biking rate up to 1
melamori03 [73]
Let x be the number of hours she jogs, and y be the number of hours she bikes.
The total time would then be x + y = 5
The total distance (based on the given speeds) would be 6x + 12y = 50
Multiply the first equation by 6 to get 6x + 6y = 30
Subtract this from the second equation to get 6y = 20
y = 10/3 or 3 1/3
Substitute this value back into the first equation to get x = 5/3 or 1 2/3
Therefore, Yolanda will have to jog 1 2/3 hours and bike 3 1/3 hours.
6 0
4 years ago
Which of the following is NOT a subset of the rational numbers
elena55 [62]
Whole numbers is the correct answer
8 0
3 years ago
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