The given variable is a continuous variable.
<h3>What is
continuous variable?</h3>
A quantitative variable can be either continuous or discrete depending on whether it is normally obtained through measurement or counting. A variable is continuous over a range of real values if it can take on any two specific real values and all other real values in between.
<h3>What is mercury thermometer?</h3>
In Amsterdam, physicist Daniel Gabriel Fahrenheit created the mercury thermometer, also known as a mercury-in-glass thermometer. It consists of a glass tube with a small diameter and a mercury bulb attached to it; the bulb contains far more mercury than the tube does.
<h3>According to the information:</h3>
A mercury thermometer was used to take the subject's temperature.
Because of the temperature:
- Not counting but measuring it.
- You can use a decimal number to represent its value.
- As a result, it is open to any value inside an interval.
- Temperature is therefore a continuous variable.
- The only format in which discrete values can be stated is as whole numbers.
so
Temperature is a continuous variable,
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The sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5
Given,
18th term of an arithmetic sequence = 8.1
Common difference = d = 0.25.
<h3>What is an arithmetic sequence?</h3>
The sequence in which the difference between the consecutive term is constant.
The nth term is denoted by:
a_n = a + ( n - 1 ) d
The sum of an arithmetic sequence:
S_n = n/2 [ 2a + ( n - 1 ) d ]
Find the 18th term of the sequence.
18th term = 8.1
d = 0.25
8.1 = a + ( 18 - 1 ) 0.25
8.1 = a + 17 x 0.25
8.1 = a + 4.25
a = 8.1 - 4.25
a = 3.85
Find the sum of 20 terms.
S_20 = 20 / 2 [ 2 x 3.85 + ( 20 - 1 ) 0.25 ]
= 10 [ 7.7 + 19 x 0.25 ]
= 10 [ 7.7 + 4.75 ]
= 10 x 12.45
= 124.5
Thus the sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5
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918x3=2754 the answer is 2757 wecome
5 rows of 10 photos and last row with 3 photos,
6 rows of 8 photos and last row with 5 photos,
7 rows of 7 photos and last row with 4 photos,
Also, reverse the rows and photos in each row (ex 5 rows 10 photos=10 rows 5 photos) to get another 3 sets.
