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vodka [1.7K]
3 years ago
5

For x, y ∈ R, prove that ||x| − |y|| ≤ |x − y|, (Hint: consider x = y + (x − y)).​

Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Using the triangular inequality (and the given hint!), we have

|x|=|(x-y)+y|\leq|x-y|+|y|\implies|x|-|y|\leq|x-y|

Similarly,

|y|=|(y-x)+x|\leq|x-y|+|x|\implies|y|-|x|\leq|x-y|\implies -|x-y| \leq |x|-|y|

We managed to bound the quantities in this fashion:

-b\leq a\leq b \implies |a|

And thus we have

||x|-|y||\leq |x-y|

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Multiple Answers

Step-by-step explanation:

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Of uncertainty that cover for a known event but you dont know the  possibilities of success.

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6 0
3 years ago
Bruh I need help ion know this stuff ​
ArbitrLikvidat [17]
I believe the answer is b and e
3 0
3 years ago
Read 2 more answers
28 ≥ 4(6x - 11)<br><br>solve for x because I get confused and I just don't understand this
LUCKY_DIMON [66]

FIrstly, distribute 4 so that it multiplies with 6x and -11: 28\geq 24x-44

Next, add 44 on both sides: 72\geq 24x

Lastly, divide both sides by 24 and <u>your answer will be 3\geq x</u>

4 0
3 years ago
What would this be??????
galina1969 [7]

Answer:

I think it's the second one(200(1.034)t = 250)

Step-by-step explanation:

if not correct me. or try the third one.

3 0
3 years ago
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