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mojhsa [17]
3 years ago
11

14

Mathematics
1 answer:
BaLLatris [955]3 years ago
3 0
I think it’s B, goodluck :))
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I have no clue how to do this. I just need to pass my online math class.
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If F(3) then 3=x. So all you would do is substitute 3 in for x
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Midtown barber shop conducts 112 haircuts per day. assume each barber works 8 hours per day and take the same amount of time to
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\cfrac{112}{8} = 14


cuts per hour. Every barber can conduct two haircuts per hour. This means that a generic number b of barbers conducts 2b cuts per hour. But we already know that the shop conducts 14 cuts per hour, so the number of barbers is given by


2b = 14 \iff b = \cfrac{14}{2} = 7

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The chemist needs the concentration of the final mixture to be 30%. how many milliliters of the 40% solution should she add to t
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Of the following, which is the solution to 2x2 + 3x = −5? (6 points) Select one: a. the quantity negative three plus or minus i
jeka94

"2x2 + 3x = −5" should be re-written as 2x^2 + 3x +5 = 0. This is a quadratic equation with a=2, b=3 and c=5. Thus, the roots are:

-3 plus or minus √(9-4[2][5])

x = ---------------------------------------------

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4 0
3 years ago
Open source textbook. A professor using an open source introductory statistics book predicts that 60% of the students will purch
Lostsunrise [7]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: Format of the statistics book the students used, categorized: "A: bought the book", "B: print the book" and "C: Online format"

The professor expects the following percentages for each category:

A: Hard copy: 60%

B: Print out: 25%

C: Online copy: 15%

At the end of the semester, the professor surveyed the students and obtained the following information

From n= 126 students,

71 bought the hard copy

30 printed the book

25 read it online

The objective of the professor is to test if the observed data follows the percentages he expected. The best way to analyze this is through a Goodness to Fit Chi-Square test.

a) The hypotheses are:

H₀: P(A)= 0.60; P(B)= 0.25; P(C)= 0.15

H₁: The observed frequencies don't adjust to the theoretical model

α: 0.05

b) For this test you can calculate the expected frequencies for each variable using the formula:

E_i= n* P_i

E_A= n * P_A= 126*0.60= 75.6\\

E_B= n * P_B= 126*0.25= 31.5

E_C= n * P_C= 126* 0.15= 18.9

Note, if the expected frequencies for all the variables are calculated corrrectly then ∑Ei= n, in this case

75.6+31.5+18.9= 126 ⇒ Is a quick way to check if the calculatios are well done, especially when you are working with more categories.

c) The conditions for this test are:

-All observartions should be independent

-The expected frequencies for all categories should be greater than 5

Ei>5

d) The statistic is:

X^2= sum \frac{(O_i-E_i)^2}{E_i} ~~X^2_{k-1}

k= number of categories of the variable

X^2_{H_0}= \frac{(71-75.6)^2}{75.6} +\frac{(30-31.5)^2}{31.5} +\frac{(25-18.9)^2}{18.9}= 2.32

This test is always one-tailed to the right, wich means that you will reject the null hypothesis to big values of X²

The critical value is X^2_{k-1;1-\alpha }= X^2_{2;0.95}= 4.303

The rejection regios is X^2_{H_0} \geq  4.303

The p-value for this test is also one-tailed to the right:

P(X₂²≥2.32)= 1 - P(X₂²<2.32)= 1 - 0.6866 = 0.3134

e) The decision rule using the p-value approach is:

If p-value ≥ α, the decision is to reject the null hypothesis.

If the p-value < α, the decision is to not reject the null hypothesis.

In this case the p-value: 0.3134 is less than the significance level I've selected α: 0.05, so the decision is to not reject the null hypothesis.

Using a level of significance of 5%, there is no significant evidence to reject the null hypothesis. Then you can conclude that the book format the students choose to use for the introductory statistics course follows the theoretical percentages expected by the professor.

I hope this helps!

8 0
3 years ago
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