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postnew [5]
3 years ago
10

How to change the expression to a single logarithm

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0
First, you'll use the "Log power rule," which says that \log_ax^p=p\log_ax. In this case, you're going from the form on the right (with p in front of the log) to the form on the left (with p in the exponent position). So, the expression becomes:

\log_7x^4+\log_7y^8+\log_7z^4

Then, you'll use the "Log product rule," which says that \log_a(xy)=\log_ax+\log_ay. Again, you're going from the form on the right to the form on the left (basically, from the sum of the logs, to a log of the products). So you get:

\log_7(x^4y^8z^4)

There's your expression simplified into a simple logarithm. 
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A) x = 3 or -1

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C)x = -7

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A) x² + 2x + 1 = 2x² - 2

Rearranging, we have;

2x² - x² - 2x - 2 - 1 = 0

x² - 2x - 3 = 0

Using quadratic formula, we have;

x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

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Multiply through by 15 to get;

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5x + 10 - 2 = 3x - 6

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x = -14/2

x = -7

C) log(2x + 3) = 2log x

From log derivations, 2 log x is same as log x²

Thus;

log(2x + 3) = logx²

Log will cancel out to give;

2x + 3 = x²

x² - 2x - 3 = 0

Using quadratic formula, we have;

x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

x = (2 ± √16)/2

x = (2 + 4)/2 or (2 - 4)/2

x = 6/2 or -2/2

x = 3 or -1

5 0
3 years ago
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