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andriy [413]
3 years ago
6

The length of each side of a square increases by 2.5 inches to form a new square with a perimeter of 70 inches. The length of ea

ch side of the original square was inches. NextReset
Mathematics
2 answers:
butalik [34]3 years ago
7 0

Answer:

The length of each side of the original square was 15 inches

Step-by-step explanation:

Let

x------> the length side of the original square

we know that

The perimeter of a square is equal to

P=4b

where

b is the length side of the square

In this problem

b=(x+2.5)\ in

P=70\ in

substitute

70=4(x+2.5)

solve for x

70=4x+10

4x=70-10

x=60/4=15\ in

Lady_Fox [76]3 years ago
4 0
Let x be the original side length of the square

P=2(l+w) 
70=2((2.5+x)+(2.5+x))
70=2(5+2x) 
70/2 = 5+2x 
35-5=2x
30=2x
15=x 

Therefore, the original length of the square was 15" 

Hope I helped :) 
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In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm
tangare [24]

Answer:

AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD

Consider right triangle CAH.By the Pythagorean theorem,

CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8

The length cannot be negative, so CD=8 cm and

CA=\sqrt{3}CD=8\sqrt{3}\ cm

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

AB=2CA=16\sqrt{3}\ cm

By the Pythagorean theorem,

BC^2=AB^2-AC^2\\ \\BC^2=(16\sqrt{3})^2-(8\sqrt{3})^2=256\cdot 3-64\cdot 3=576\\ \\BC=24\ cm

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Murljashka [212]

Answer:

1.33

Step-by-step explanation:

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