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3 years ago

What is the formula for ANOVA

1 answer:

8 0

P = 3
n = 5
N = 15
x ¯ = 16
SST = ∑n(x−x ¯ ) 2 
SST = 5(12−16) 2 +5(16−16) 2 +11(20−16) 2 
= 160
MST = SSTp−1 
MST = 1603−1 
= 80
SSE = ∑(n−1)S 2 
SSE = 4*4 + 4*1 + 4*16
= 84
MSE = SSEN−p 
MSE = 8415−3 
MSE = 7
F = MSTMSE 
F = 807 
= 11.429

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The rental car agency has 30 cars on the lot. 10 are in great shape, 16 are in good shape, and 4 are in poor shape. Four cars ar

Korolek [52]

Complete Question:

The rental car agency has 30 cars on the lot. 10 are in great shape, 16 are in good shape, and 4 are in poor shape. Four cars are selected at random to be inspected. Do not simplify your answers. Leave in combinatorics form. What is the probability that:

a. Every car selected is in poor shape

b. At least two cars selected are in good shape.

c. Exactly three cars selected are in great shape.

d. Two cars selected are in great shape and two are in good shape.

e. One car selected is in good shape but the other 3 selected are in poor shape.

Answer:

$P_A = \frac{^4 C_4}{^{30}C_{4}}$

$P_B = \frac{[^{16} C_2 *^{14} C_2 ] +[^{16} C_3 *^{14} C_1 ] + ^{16} C_4}{^{30}C_{4}}$

$P_C = \frac{^{10} C_3 *^{20} C_1 }{^{30}C_{4}}$

$P_D = \frac{^{10} C_2 *^{16} C_2 }{^{30}C_{4}}$

$P_E = \frac{^{16} C_1 *^{4} C_3 }{^{30}C_{4}}$

Step-by-step explanation:

From the question we are told that

The number of car in the parking lot is n = 30

The number of cars in great shape is k = 10

The number of cars in good shape is r = 16

The number of cars in poor shape is q = 4

The number of cars that were selected at random is N= 4

Considering question a

Generally the number of way of selecting four cars that are in a poor shape from number of cars that are in poor shape is

$^{q} C_{N}$

=> $^{4} C_{4}$

Here C stands for combination.

Generally the number of way of selecting four cars that are in a poor shape from total number of cars in the parking lot is

$^{n} C_{N}$

=> $^{30} C_{4}$

Generally the probability that every car selected is in poor shape is mathematically represented as

$P_A = \frac{^4 C_4}{^{30}C_{4}}$

Considering question b

Generally the number of way of selecting 2 cars that are in good shape from number of cars that are in good shape is

$^{r} C_{2}$

=> $^{16} C_{2}$

Here C stands for combination.

Generally the number of way of selecting the remaining 2 cars from the remaining number of cars in the parking lot is

$^{n-r} C_{2}$

=> $^{30-16} C_{2}$

=> $^{14} C_{2}$

Generally the number of way of selecting 3 cars that are in good shape from number of cars that are in good shape is

$^{r} C_{3}$

=> $^{16} C_{3}$

Generally the number of way of selecting the remaining 1 cars from the remaining number of cars in the parking lot is

$^{n-r} C_{1}$

=> $^{30-16} C_{1}$

=> $^{14} C_{1}$

Generally the number of way of selecting 4 cars that are in good shape from number of cars that are in good shape is

$^{r} C_{4}$

=> $^{16} C_{4}$

Generally the probability that at least two cars selected are in good shape

$P_B = \frac{[^{16} C_2 *^{14} C_2 ] +[^{16} C_3 *^{14} C_1 ] + ^{16} C_4}{^{30}C_{4}}$

Considering question c

Generally the number of way of selecting 3 cars that are in great shape from number of cars that are in great shape is

$^{k} C_{3}$

=> $^{10} C_{3}$

Generally the number of way of selecting the remaining 1 cars from the remaining number of cars in the parking lot is

$^{n-k} C_{1}$

=> $^{30-10} C_{1}$

=> $^{20} C_{1}$

Generally the probability of selecting exactly three cars selected are in great shape is

$P_C = \frac{^{10} C_3 *^{20} C_1 }{^{30}C_{4}}$

Considering question d

Generally the number of way of selecting 2 cars that are in good shape from number of cars that are in good shape is

$^{r} C_{2}$

=> $^{16} C_{2}$

Generally the number of way of selecting 2 cars that are in great shape from number of cars that are in great shape is

$^{k} C_{2}$

=> $^{10} C_{2}$

Generally the probability that two cars selected are in great shape and two are in good shape.

$P_D = \frac{^{10} C_2 *^{16} C_2 }{^{30}C_{4}}$

Considering question e

Generally the number of way of selecting 1 cars that is in good shape from number of cars that are in good shape is

$^{r} C_{1}$

=> $^{16} C_{1}$

Generally the number of way of selecting 3 cars that are in a poor shape from number of cars that are in poor shape is

$^{q} C_{3}$

=> $^{4} C_{3}$

Generally the probability that one car selected is in good shape but the other 3 selected are in poor shape is

$P_E = \frac{^{16} C_1 *^{4} C_3 }{^{30}C_{4}}$

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3 years ago

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antiseptic1488 [7]

4) 62.8 cm^2
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3 years ago

Read 2 more answers

ASAP please help!!!

Serggg [28]

Y+4<9
subtract 4
y<5
y is smaller than and equal to 5
so you shade from 5 to the negative end to infinity (to the left) and shade the 5 to show that it is included (attachment says A)

6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)

-6+2x>8
add 6
2x>14
divide 2
x>7
so
x is bigger than 7
shade from 7 to the positive end to infinity (to the right) and don't shade 7 but put a circle around it to show that it is not included (attachment says B )

I have included pictures of the number lines

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3 years ago

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antoniya [11.8K]

Answer:

Step-by-step explanation:

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3 years ago

you are given an 8-gallon jug filled with water and also two empty jugs: one that holds 5 gallons and other that holds 3 gallons

Yanka [14]

Answer:

Step-by-step explanation:

We will use following steps to measure exactly 4 gallons of water with the help of 5 gallons and 3 gallons empty jugs.

1). Fill 3 gallons jug completely.

2). Pour this 3 gallons of water into 5 gallons jug. Now we have 3 gallons of water in 5 gallons jug and 3 gallons jug empty.

We can add 2 gallons of water in the empty space of 5 gallons jug more.

3). Fill the 3 gallons jug with the water again.

4). Pour this water into 5 gallons jug which can hold 2 gallons of water more.

Now we have 5 gallons of jug filled fully and 1 gallon water remaining in the 3 gallons jug.

5). Empty the 5 gallons jug completely.

6). Pour the remaining 1 gallon of remaining water in 3 gallons jug into 5 gallons jug.

7). Fill the 3 gallons jug completely and pour it into 5 gallon jug.

8). Finally we have 4 gallons of water in the 5 gallons jug.

8 0

3 years ago