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Ket [755]
3 years ago
5

What is the value of 5^3i^9?

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

\displaystyle 125^i

Step-by-step explanation:

<u>Extended Information </u><u>on</u><u> </u><u>the</u><u> Complex Number System</u>

\displaystyle \sqrt{-1} = i \\ -1 = i^2 \\ -i = i^3 \\ 1 = i^4\:[all\:multiples\:of\:four]

I am joyous to assist you at any time.

All work is shown above. ↑

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10 times as much as blank hundred is 70 hundreds or blank thousands
netineya [11]

Answer:

10 times as much as 7 hundred is 70 hundreds or 7 thousands.

Step-by-step explanation:

The question given is:

10 times as much as _____ hundreds is 70 hundreds or _____ thousands.

Dividing the question into two fractions, we have:

10 times what is 70 hundreds?

What is 70 hundreds in thousands?

10 x 7 hundred = 10 x 700 = 70 hundreds

Recall that 70 hundreds = 70 00

70 hundreds = 70 00 = 7 thousands = 7 000

Therefore, the question can be written as:

10 times as much as 7 hundreds is 70 hundreds or 7 thousands.

7 0
3 years ago
A parabola passes through the points (–5, –10) and (5, –10), and the vertex is located at (0, 0). Find the equation of the parab
vitfil [10]
The equation of the parabola is -0.4x^2
8 0
3 years ago
What is the Range of this data
musickatia [10]
The range of this data is 65 since the minimum is 20 and the maximum is 85(if its counting by 5s) then you just subtract and you have the range.
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3 years ago
Mr. Cooper is making homework packets. He will put 6 worksheets in each packet. There are 18 worksheets. How many packets can he
ziro4ka [17]

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8 0
3 years ago
Consider the equations y = √x and y = x^2 - 1
lord [1]
<h3>Answer:</h3>

(x, y) ≈ (1.49021612010, 1.22074408461)

<h3>Explanation:</h3>

This is best solved graphically or by some other machine method. The approximate solution (x=1.49, y=1.221) can be iterated by any of several approaches to refine the values to the ones given above. The values above were obtained using Newton's method iteration.

_____

Setting the y-values equal and squaring both sides of the equation gives ...

... √x = x² -1

... x = (x² -1)² = x⁴ -2x² +1 . . . . . square both sides

... x⁴ -2x² -x +1 = 0 . . . . . polynomial equation in standard form.

By Descarte's rule of signs, we know there are two positive real roots to this equation. From the graph, we know the other two roots are complex. The second positive real root is extraneous, corresponding to the negative branch of the square root function.

8 0
3 years ago
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