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Arlecino [84]
3 years ago
10

Simplify the square root of 320

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0
17.89, is this an option?
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Find the value of x to the nearest tenth.
BlackZzzverrR [31]

Answer:

x = 8.0

Step-by-step explanation:

sin theta = opposite/ hypotenuse

sin 53 = x/10

Multiply by 10 on each side

10 sin 53= x

7.9863551 =x

Rounding to the nearest tenth

8.0 =x

4 0
2 years ago
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What is .333 written in its simplest fraction from
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Hi.
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3 years ago
Find the volume of the sphere. Round your answer to the nearest tenth.
ollegr [7]

Answer:

Step-by-step explanation:

Givens

pi = 3.14

d = 3.8

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6 0
2 years ago
What fraction of the pizza did each of her friends get if they split it evenly?
eimsori [14]

Answer: the answer has to be number 3if I’m not mistaking

Step-by-step explanation:

I took this test last year

4 0
2 years ago
A 2?-ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles.
navik [9.2K]

Answer: A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

Step-by-step explanation:

Since we have given that

Radius of inner circle = 57 ft

As we know the formula for "Circumference of circle":

Distance=Circumference=2\pi r\\\\Distance=2\times \frac{22}{7}\times 57\\\\Distance=358.28\ Ft

Since we have also mentioned that there is 2 feet wide circular track for a camera dolly.

So, Radius of outer circle will be given as

57+2\\=59\ ft

So, Distance = Circumference is given by

Distance=2\pi R\\\\Distance=2\times \frac{22}{7}\times 59\\\\Distance=370.85\ ft

Hence, Difference between the outer rail travel than a wheel on the inner rail travel is given by

370.85-358.28\\\\=12.57\ ft

Therefore, A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

7 0
3 years ago
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