Pi r² is circle's area expression.
So the r is radius,.
Answer: They are similar many ways.
Step-by-step explanation:
1. There is a law that guides both of them. Because each has a strick law.
2. They both need practice. Practice they say makes one perfect. When u practice both of them, you become familiar on how to use them.
3. The brain has to read meaning to either of the two to be able to be able to learn a pattern of learn.
4. Both language and functions are systems. They are made of different parts, language is made up of different words while function is made up of axioms which theorems.
Answer:
The probability that Joe's stock will go up and he will win in the lottery is 0.00005.
Step-by-step explanation:
Let the events be denoted as:
<em>X</em> = the stock goes up
<em>Y</em> = Joe wins the lottery
Given:
P (X) = 0.50
P (Y) = 0.0001
The events of the stock going up is not dependent on the the event of Joe winning the lottery.
So the events <em>X</em> and <em>Y</em> are independent of each other.
Independent events are those events that can occur together at the same time.
The joint probability of two independent events <em>A</em> and <em>B </em>is,
Compute the value of P (<em>X ∩ Y</em>) as follows:
Thus, the probability that Joe's stock will go up and he will win in the lottery is 0.00005.
Answer:
height of cylinder = 4/3 h
Step-by-step explanation:
The solid has a cylinder surmounted with a cone .Therefore, the volume of the solid is the sum of the cone and the cylinder.
volume of the solid = volume of cylinder + volume of cone
volume of the solid = πr²h + 1/3πr²h
let
height of the cylinder = H
recall
the height of the cone = 2h
volume of the solid = πr²h + 1/3πr²h
3(1/3πr²2h) = πr²H + 1/3πr²2h
2πr²h = πr²H + 2/3 πr²h
πr²(2h) = πr²(H + 2/3 h)
divide both sides by πr²
2h = H + 2/3 h
2h - 2/3h = H
H = 6h - 2h/3
H = 4/3 h
height of cylinder = 4/3 h
Answer:
0.3333 (the three continues)
Step-by-step explanation:
If you put 1/3 or 1 divided by 3 in the calculator, then it'll show the decimal form of the fraction.
