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Kisachek [45]
3 years ago
11

Let A be the set of all lines in the plane. Define a relation R on A as follows. For every l1 and l2 in A, l1 R l2 ⇔ l1 is paral

lel to l2. (Assume that a line is parallel to itself). Which of the following is true for R?
A. R is reflexive.
B. R is symmetric.
C. R is transitive.
D. R is neither reflexive, symmetric, nor transitive.
Mathematics
1 answer:
Lyrx [107]3 years ago
7 0

Answer:

Hence, the relation R is a reflexive, symmetric and transitive relation.

Given :

A be the set of all lines in the plane and R is a relation on set A.

R=\{l_1,l_2\in A|l_1 \;\text{is parallel to}\; l_2\}

To find :

Which type of relation R on set A.

Explanation :

A relation R on a set A is called reflexive relation if every a\in A then (a,a)\in R.

So, the relation R is a reflexive relation because a line always parallels to itself.

A relation R on a set A is called Symmetric relation if (a,b)\in R then (b,a)\in R for all a,b\in A.

So, the relation R is a symmetric relation because if a line l_1 is parallel to the line l_2 the always the line l_2 is parallel to the line l_1.

A relation R on a set A is called transitive relation if (a,b)\in R and (b,c)\in R then (a,c)\in R for all a,b,c\in A.

So, the relation R is a transitive relation because if a line l_1 s parallel to the line l_2 and the line l_2 is parallel to the line l_3 then the always line l_1 is parallel to the line l_3.

Therefore the relation R is a reflexive, symmetric and transitive relation.

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Step-by-step explanation:

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FOR y=-3

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Hence, the table becomes:

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9                    4

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Step-by-step explanation:

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This indicates that the individuals taking vitamin C were 53% less likely to catch a cold and that taking vitamin C has a protective effect, making them less likely to catch a cold.

This is further explained below.

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1 year ago
In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour
Lesechka [4]

Answer:

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=54 represent the sample mean  

\mu population mean (variable of interest)

\sigma=21 represent the sample standard deviation

n=16 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=1-0.9=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

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