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torisob [31]
3 years ago
15

What is 160.9-55.23+27.1

Mathematics
2 answers:
dem82 [27]3 years ago
7 0
The answer to your problem is 132.77
PolarNik [594]3 years ago
5 0
132.77 is the answer
You might be interested in
Please answer this question now
xz_007 [3.2K]

Answer:

397.7 m²

Step-by-step Explanation:

Step 1: find m < W

W = 180 - (33+113) (sum of ∆)

W = 34°

Step 2: find side UV using the law of sines

\frac{UV}{sin(W)} = \frac{VW}{sin(U)}

\frac{UV}{sin(34)} = \frac{29}{sin(33)}

Multiply both sides by sin(34)

\frac{UV}{sin(34)}*sin(34) = \frac{29}{sin(33)}*sin(34)

UV = \frac{29*sin(34)}{sin(33)}

UV = 29.8 m (approximated)

Step 3: find the area using the formula, ½*UV*VW*sin(V)

area = ½*29.8*29*sin(113)

Area = 397.7 m² (rounded to the nearest tenth.

7 0
3 years ago
(a) It takes the Earth 365 days to complete a full orbit around the sun. It takes Jupiter approximately 4,332 days, 14 h, and 9
kogti [31]

1 year = 365 days.

1 day = 24 hours.

1 hour = 60 minutes.

First convert the hours and minutes in Jupiter orbit to days:

14*60 = 840 +9 = 849 minutes.

849 / 60 = 14.15 hours.

14.15 / 24 = 0.59 days.

Jupiter's orbit is 4332.59 days.

Now divide that by 365 for the number of years:

4332.59 / 365 = 11.87 years.

5 0
3 years ago
In circle Y what is m angel 1 <br><br> 6<br> 25<br> 31<br> 37
BigorU [14]

The answer is definitely 31

7 0
3 years ago
Read 2 more answers
Carolyn and Linda each saw a movie on Friday.
jonny [76]
15 minutes is the answer
3 0
3 years ago
Read 2 more answers
Two lines, C and D, are represented by the equations given below:
lakkis [162]

y=x+14 line 1

y=3x+2 line 2

These are both the equation of lines written in slope intercept form

y=mx+b where m is the slope and the point (0,b) is the y intercept.

The first line has a slope of m=1. The 2nd line has a slope of m=3

Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.

We already have y solved in terms of x from either equation so we can use substitution to solve the system.

Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.

x+14=3x+2

solve for x.

Subtract x from both sides...

14= 3x-x+2

14=2x+2

subtract 2 from both sides

14-2=2x

12=2x

divide both sides by 2

6=x

We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.

y=6+14

y=20

These two lines cross at the point (6,20) which is a point the two lines have in common.

Hope I helped (SharkieOwO)

3 0
3 years ago
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