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kvasek [131]
3 years ago
12

Solve the simultaneous equations3x-5y=5​ and x+10y=4

Mathematics
1 answer:
bulgar [2K]3 years ago
7 0
3x - 5y = 5 ——> 6x - 10y = 10

6x - 10y = 10
x + 10y = 4
——————-
5x = 6
x = 1.2

1.2 + 10y = 4
10y = 2.8
y = 0.28

so, x = 1.2 and y = 0.28

hope this helps :)
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Adding mixed numbers. Can someone help me correct my answer?
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Answer:

27 13/60

Step-by-step explanation:

What you have tried to do is not an impossible way to do it. What you could do is set your fractions and whole numbers like this.

( 7 + 1/10) * (3 + 5/6) I don't know if you know what FOIL is, but that is the way to proceed.

  • First: (meaning the first in each factor ).   3 * 7 =                                    21
  • Outside: (meaning the two terms near outside the brackets) 7 * 5/6 = 5 5/6
  • Inside: The two terms closest to the * sign      1 / 10  *3 =                         3/10
  • Last: The two end terms    (1/10 * 5/6 = 5/60                                              5/60

Now you can add. 21 + 5 is the whole number amount = 26

Add the fractions

  • 5/6 + 3/10 + 5/60 The lowest common multiple is 60
  • 50/60 + 18/60 +5/60 = 73 / 60 = 1 and 13/60

Add that to 26 and you get 27 13/60

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3 years ago
A bottling process is inspected 100 percent of the time because of the low yield rate of 98%. If a batch of 80 bottles are inspe
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Answer:

The probability is   P(X <  3) =  0.7843

Step-by-step explanation:

From the question we are told that

   The low yield rate is  q = 0.98

    The sample size n = 80

Hence the probability that the bottle is bad

       p = 1- q

=>    p = 1 - 0.98

=>     p =0.02

Generally the distribution of yield follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators  

Generally the probability less than three bottles are bad is mathematically represented as

    P(X <  3) = P(X = 0 ) + P(X = 1 )+ P(X = 2)

=>  P(X <  3) = ^{80}C_0 *  0.02^0 *  (1- 0.02)^{80-0} +^{80}C_1 *  0.02^1 *  (1- 0.02)^{80-1}+ ^{80}C_2 *  0.02^2 *  (1- 0.02)^{80-2}

=>  P(X <  3) = 1 *  1 * 0.1986 + 80 *  0.02 *  0.2027 + 3160 *  0.0004 * 0,2068

=>  P(X <  3) =  0.7843

8 0
3 years ago
Read 2 more answers
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