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3 years ago

(20 points) Simplify The Expression with work/steps (8+3i) + (-2+ i)

Mathematics

1 answer:

zimovet [89]3 years ago

6 0

Given the expression (8+3i)+(-2+i)

We need to simplify it.

(8+3i)+(-2+i)

First we have to remove the parenthesis.

8+3i-2+i

As we know that multiplication of positive and negative is negative.

Now we will add or subtract like terms. Like terms means here i with i and constant term with constant term. So here we will add 3i and i. Also subtract 2 from 8.

8-2 +3i+i

6+4i

We have got the required answer.

The simplified answer is 6+4i.

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Step-by-step explanation:

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3 years ago

The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de

OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean $\mu$ = 186 × 17 = 3162

Standard deviation = $29* \sqrt{17}$

Standard deviation = 119.57

$P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})$

$P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})$

$P(X>3417) = P(Z>\dfrac{255}{119.57})$

$P(X>3417) = P(Z>2.133)$

$P(X>3417) =1- 0.9834$

$P(X>3417) =0.0166$

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

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3 years ago

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C I think but I’m not suuuper sure

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2 years ago