Answer:
Step-by-step explanation:
The question lacks the required diagram. Find the diagram attached below;
According to the first triangle, taking 30° as the reference angle, the opposite side of the triangle will be 5 and the adjacent will be the unknown side "b"
According to SOH, CAH, TOA;
tanθ = opposite/adjacent (using TOA)
Given;
θ = 30°, opposite = 5 and adjacent = b
tan30° = 5/b
b = 5/tan30°
b = 5/(1/√3)
b = 5*√3/1
b = 5√3
According to the 45° triangle, the opposite side of the triangle will be d and the hypotenuse will be 7
Using SOH;
sinθ = opposite/hypotenuse
Given;
θ = 45°, opposite = d and adjacent = 7
sin45° = d/7
d = 7sin45°
d = 7(1/√2)
d = 7/√2
Rationalize 7/√2
= 7/√2*√2/√2
=7√2/2
Hence the value of d is 7√2/2
Deena has included the discount on the wrong side of the equation.
So we have -23 degrees to start
Then add 5 to it
It becomes -23+5=-18
Now subtract 7 from that so -18-7=-25 degrees
Hope this helps