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3 years ago

I dont understand this

Mathematics

1 answer:

MrRa [10]3 years ago

8 0

Answer: First option.

Step-by-step explanation:

You need to remember the following Trigonometric Identity:

$cos\alpha =\frac{adjacent}{hypotenuse}$

In this case, you can identify in the figure that:

$\alpha =35\°\\adjacent=9\\hypotenuse=x$

Then you must substitute these values into $cos\alpha =\frac{adjacent}{hypotenuse}$ :

$cos(35\°) =\frac{9}{x}$

Finally, you need to solve for "x" in order to find its value. This is:

$(x)(cos(35\°))=9\\\\x=\frac{9}{cos(35\°)}\\\\x=10.98$

Rounding the result to the nearest tenth, you get:

$x\approx11$

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Solve the system of equations using elimination: -8x-4y=4 and -5x-y=-11.

ziro4ka [17]

The solutions to the given system of equations are x = 4 and y = -9

<h3>Simultaneous linear equations</h3>

From the question, we are to determine the solutions to the given system of equations

The given system of equations are

-8x-4y=4 --------- (1)

-5x-y=-11 --------- (2)

Multiply equation (2) by 4

4 ×[-5x-y=-11 ]

-20x -4y = -44 -------- (3)

Now, subtract equation (3) from equation (1)

-8x -4y = 4 --------- (1)

-(-20x -4y = -44) -------- (3)

12x = 48

x = 48/12

x = 4

Substitute the value of x into equation (2)

-5x -y = -11

-5(4) -y = -11

-20 -y = -11

-y = -11 + 20

-y = 9

∴ y = -9

Hence, the solutions to the given system of equations are x = 4 and y = -9

Learn more on Simultaneous linear equations here: brainly.com/question/26310043

#SPJ1

6 0

1 year ago

Converse of the Pythagorean theorem

jonny [76]

I only know how to do # 7.

7. 4.5^2 + 6^2 = 7.5^2
20.25 + 36 = 56.25
56.25 = 56.25

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7 0

3 years ago

Three vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.

topjm [15]

Given:

The three vertices of a parallelogram are (-3,8), (4,5), (2,-5).

To find:

The fourth vertex of the parallelogram.

Solution:

Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).

We know that, diagonals of a parallelogram bisect each other. It means midpoints of both diagonals are same.

Midpoint formula:

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

Two diagonals of ABCD are AC and BD.

Midpoint of AC = Midpoint of BD

$\left(\dfrac{-3+2}{2},\dfrac{8-5}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)$

$\left(\dfrac{-1}{2},\dfrac{3}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)$

On comparing both sides, we get

$\dfrac{4+a}{2}=\dfrac{-1}{2}$

$4+a=-1$

$a=-1-4$

$a=-5$

And,

$\dfrac{5+b}{2}=\dfrac{3}{2}$

$5+b=3$

$b=3-5$

$b=-2$

Therefore, the coordinates of fourth vertex are (-5,-2).

3 0

2 years ago

This ones tricky can yall do it?

Ray Of Light [21]

Answer:

City A, City C

Step-by-step explanation:

They are all below -3 degrees Celsius

4 0

3 years ago

Read 2 more answers

PLZ HELP 70 POINTS!!!!!

marin [14]

5^(x+7)=(1/625)^(2x-13)

We move all terms to the left:

5^(x+7)-((1/625)^(2x-13))=0

Domain of the equation: 625)^(2x-13))!=0

x∈R

We add all the numbers together, and all the variables

5^(x+7)-((+1/625)^(2x-13))=0

We multiply all the terms by the denominator

(5^(x+7))*625)^(2x+1-13))-((=0

We add all the numbers together, and all the variables

(5^(x+7))*625)^(2x-12))-((=0

We add all the numbers together, and all the variables

(5^(x+7))*625)^(2x=0

not sure if this is right :/

8 0

3 years ago

Read 2 more answers