![y'''+2y''-4y'-8y=0](https://tex.z-dn.net/?f=y%27%27%27%2B2y%27%27-4y%27-8y%3D0)
has characteristic equation
![r^3+2r^2-4r-8=r^2(r+2)-4(r+2)=(r^2-4)(r+2)=(r-2)(r+2)^2=0](https://tex.z-dn.net/?f=r%5E3%2B2r%5E2-4r-8%3Dr%5E2%28r%2B2%29-4%28r%2B2%29%3D%28r%5E2-4%29%28r%2B2%29%3D%28r-2%29%28r%2B2%29%5E2%3D0)
which has roots at
![r=\pm2](https://tex.z-dn.net/?f=r%3D%5Cpm2)
. The negative root has multiplicity 2. So the general solution is
The answer
according to the figure, we can solve this problem only by applying sines rule:
that is
sinA/a = sinB/b = sinC /c
As we observe, sin A /54 = sin B/27 = sin C/ c, and c = AB
besides, sinC > sinB > sinA , so the only answer possible is
<span>27 < AB < 81</span>
Answer: Solution: (12, 3)
Step-by-step explanation:
2x - 4y = 12
3x + 4y = 48
Add both equations
5x = 60
Divide both sides by 5
x = 12
We can use the value of x to find y
3x + 4y = 48
3 (12) + 4y = 48
36 + 4y = 48
Subtract 36 from both sides
4y = 12
Divide both sides by 4
y = 3
Solution: (12, 3)
Answer:
yea by using a resipe
Step-by-step explanation: