Mark is in training for a marathon race. He has been training by running 10 miles each day. He will be increasing his running by
this weekly formula: y = 10 (1.1 )x, where y is the number of miles he will run each day, x weeks from now. Compute the distance Mark will run each day for 52 weeks (one year) from now using the formula. Does this distance seem reasonable?
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1 answer:
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Answer:
- 5 min: 3,029,058
- 10 min: 3,398,220
- 60 min: 10,732,234
Step-by-step explanation:
The given function is evaluated by substituting the given values of t. This requires using the exponential function of your calculator with a base of 'e'. Many calculators have that value built in, or have an e^x function (often associated with the Ln function).
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<h3>5 minutes</h3>The number of bacteria present after 5 minutes is about ...
f(5) = 2.7×10^6×e^(0.023×5) ≈ 3,029,058
<h3>10 minutes</h3>The number of bacteria present after 10 minutes is about ...
f(10) = 2.7×10^6×e^(0.023×10) ≈ 3,398,220
<h3>60 minutes</h3>The number of bacteria present after 60 minutes is about ...
f(60) = 2.7×10^6×e^(0.023×60) ≈ 10,732,234
