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nekit [7.7K]
3 years ago
15

Write a coordinate proof given quadrilateral ABCD with vertices A (3, 2), B (8, 2), C (5, 0), and D (0, 0).

Mathematics
1 answer:
sergey [27]3 years ago
8 0

Answer:

Step-by-step explanation:

Hhahahahahahahahhahahahahahaha

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2a-6=4a<br><br> Solve for a<br><br> Check your work
algol [13]

Answer:

-3

Step-by-step explanation:

2a - 6 = 4a

subtract 2a giving you -6 = 2a

divide by 2 from both sides so that a will be by itself

giving you -6 ÷ 2 = a

-6 ÷ 2 = -3

so a = -3

5 0
3 years ago
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Kay [80]
He rounded to the hundredths place.
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4 years ago
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Answer:

A B and D

Step-by-step explanation:

4 0
3 years ago
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[6.01] Systems of equations with different slopes and different y-intercepts have more than one solution.
scoundrel [369]
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4 0
3 years ago
Look at the graph shown below:
ElenaW [278]
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

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\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad &#10;\begin{array}{llll}&#10;\textit{plug in the values for }&#10;\begin{cases}&#10;y_1=4\\&#10;x_1=0\\&#10;m=\boxed{?}&#10;\end{cases}\\&#10;\textit{and solve for "y"}&#10;\end{array}\\&#10;\left. \qquad   \right. \uparrow\\&#10;\textit{point-slope form}

once you get the slope and solve for "y", that'd be the equation of the line.
7 0
3 years ago
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