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3 years ago

6

The janitor at a school discovered a leak in a pipe. The janitor found out that it was leaking at a rate of 14 oz per hour. How

fast was the pipe leaking in gallons per day?

1 answer:

umka2103 [35]3 years ago

7 0

2.625 gallons a day

14 oz x 24 hours = 336 oz per day

336 oz converted to gallons is 2.625 gallons

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A triangle forms the front of the Pantheon in Rome, Italy. Classify the triangle based on its sides. Then classify it based on i

SVETLANKA909090 [29]

Answer:

(See explanation for further details)

Step-by-step explanation:

Classification based on sides:

Equilateral - Three sides with same length.

Isosceles - Two sides with same length.

Scalene - No sides with same length.

Classification based on sides:

Acute-Angled - All angles are acute. $(0^{\circ} < \theta < 90^{\circ}, 0^{\circ} < \alpha < 90^{\circ}, 0^{\circ} < \beta < 90^{\circ}, \theta + \alpha + \beta = 180^{\circ})$

Right-Angled - One angle is right. $(0^{\circ} < \theta < 90^{\circ};\alpha = 90^{\circ}, 0^{\circ} < \beta < 90^{\circ}, \theta + \alpha + \beta = 180^{\circ})$

Obtuse-Angled - One angle is obtuse. $(0^{\circ} < \theta < 90^{\circ},90^{\circ}$

3 0

2 years ago

30 men repair a road in 56 days by working 6 hours daily. In how many days 45 men will repair the same road by working 7 hours d

svetoff [14.1K]

Step-by-step explanation:

(30 men, 56 days, 6 hours daily)

=> (30 men, 48 days, 7 hours daily)

=> (45 men, 32 days, 7 hours daily)

Hence it will take 32 days.

5 0

2 years ago

Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4

Alina [70]

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of (-9,-8) and (7,-4)

midpoint formula is

$\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}$

$\frac{-9+7}{2} ,\frac{-8+-4}{2}$

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

$slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}$

$slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}$

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4 and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10

3 0

3 years ago

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

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3 years ago

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Llana [10]

Answer:

What do you need help with?!?XD

Step-by-step explanation:

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3 years ago