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3 years ago

What is the reason that m<2 and m<3 are supplementary

Mathematics

1 answer:

katen-ka-za [31]3 years ago

6 0

Answer:

see explanation

Step-by-step explanation:

∠2 and ∠3 are same- side interior angles and are supplementary.

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Help plz I've been stuck

stepladder [879]

Answer:

The answer is D. $(\frac{1}{5} )^{2}$

Step-by-step explanation:

$5^{4} *(5^{-3} )^{2}$

simplify the expression by multiplying

$5^{4} *5^{-6}$

calculate the product

$5^{-2}$

express with a positive exponent using $a^{-n} =\frac{1}{a^{n} }$

$\frac{1}{5^{2} }$

6 0

3 years ago

Read 2 more answers

What is the answer for each sentence

Harman [31]

Answer:

1. surface area, 2. volume. 3. surface area, 4. volume

Step-by-step explanation:

The stain means it's just the surface of the box, and not what can go in it.

the question is asking how many shoe boxes can fit IN

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3 years ago

The tar contents of 8 brands of cigarettes selected at random from the latest list released by the federal Trade Commission is a

sattari [20]

The mean is 11.7 i don't know the Variance

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3 years ago

There are some counters in a bag.

iVinArrow [24]

Answer:

187

Step-by-step explanation:

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2 years ago

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago