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2 years ago

How do you solve a slope for a parallel/perpendicular line?

1 answer:

4 0

The slope of a perpendicular line is the opposite of the reciprocal (negative to positive or positive to negative and then flip the fraction) and the parallel lines have the same slope

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How to evaluate and simplify <br>

Kobotan [32]

Answer:

depends.

Step-by-step explanation:

Evaluating a question depends on the question given. To simplify an answer, you need to find the simplest answer, this process also depends on what question you're given, for example, if you simplify 4/8 (four eighths), it would be 1/2 (one half).

6 0

2 years ago

The figure is rotated 360° clockwise with the origin as the center of rotation. Which graph represents the rotated figure?

Scilla [17]

Given

The figure is rotated 360° clockwise with the origin as the center of rotation. Which graph represents the rotated figure?

Answer

After the rotation of 360 degrees, a figure comes back to original position

Option A is correct

4 0

6 months ago

2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA

professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

$A=45e^{-0.0045(t)}$

a) To find the initial amount of this substance

At t=0, we get

$A=45e^{-0.0045(0)}$ $A=45e^0$

We know that e^0=1 ( anything to the power zero is 1)

we get,

$A=45$

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

$\frac{45}{2}=45e^{-0.0045(t)}$

$\frac{1}{2}=e^{-0.0045(t)}$

Taking natural logarithm on both sides we get,

$\ln (\frac{1}{2})=-0.0045(t)^{}$ $(-1)\ln (\frac{1}{2})=0.0045(t)$ $\ln (\frac{1}{2})^{-1}=0.0045(t)$ $\ln (2)=0.0045(t)$ $0.6931=0.0045(t)$ $t=\frac{0.6931}{0.0045}$ $t=154.02$

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

$A=45e^{-0.0045(2500)}$ $A=45e^{-11.25}$ $A=45\times0.000013=0.000585$ $A=0.000585$

The amount of substance will be present around in 2500 years is 0.000585 grams

4 0

5 months ago

State the practical meaning of the slope and y-intercept for the situation described. The cost, in dollars, of retaining the ser

Anuta_ua [19.1K]

The practical meaning of the slope and y - intercept of the linear equation, C = 48x + 18 is that 48x is the variable cost depending on the number of hours and 18 is the fixed cost or the overhead change. Hence, the answer to the question above is letter A.

6 0

2 years ago

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PLEASE HELP!! With explanation/solution please!!

Tema [17]

Step-by-step explanation:

Just sum the number of cows and buffaloes:

2p^2 - p + 4 + p^2 + p + 1 = 3p^2 +5 animals.

5 0

1 year ago

Read 2 more answers