The amswer is -24, just gotta do division and subtration
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Use the trick x+ y+ z =0 and 6+8+z=0,...so z= -14
Answer:
joe mama-
Step-by-step explanation:
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