d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
Answer:
Step-by-step explanation:
I learned this easy way to complete the sqare in the fastest way possible
First you want to get it to x^2. So the first thing you would do is divide the entire equation by 2 to get 2(x^2 -5/2x +3/2). then you do one half of b or in this case -5/2. That would make -5/4. you would put this into the factor.
2( x -5/4 + ) ( x -5/4 - )
Then you square that number (-5/4)
That makes 25/16. you take that number and subtract the last number or the constant, c to make 1/16. now to finish it up you square root that number. the squre root of 1/16 is 1/4. then you put that into the last part of the factor.
2( x -5/4 + 1/4) ( x -5/4 - 1/4)
Then you simplify
(x-1) 2(x-3/2)
(x-1) (2x-3)
now to make sure I am correct, I will re-multiply it out
2x^2 -5x + 3
Answer:
Incorrect
Step-by-step explanation:
Juanita is incorrect because she shouldn't be using 2 squared.
Answer:
Step-by-step explanation:
espero que este sea el resultado :(
Answer:
R=30.81≈31
Step-by-step explanation:
