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3 years ago

Please help!!!! I’ll mark you as brainliest if correct

Mathematics

2 answers:

vampirchik [111]3 years ago

8 0

Answer:

You are correct

Step-by-step explanation:

The mode is the value that occurs most often is a data set

The median is the value in the middle

Mean is the average of all the points

Range is the largest minus the smallest

zhuklara [117]3 years ago

5 0

Answer:

1. A

2. D

Step-by-step explanation:

Good job you had them right already!! (:

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The surface area of a cube is represented by the expression below, where s is the side length of the cube. Find the surface area

Dmitry [639]

Answer:

486 centimeters³

Step-by-step explanation:

Surface area of a cube = 6s²

Where,

s = side length

Find the surface area of a cube-shaped jewelry gift box with a side length of 9 centimeters.

s = 9 centimeters

Surface area of a cube = 6s²

= 6 × 9²

= 6 × 81

= 486 centimeters³

Surface area of a cube-shaped jewelry gift box with a side length of 9 centimeters 486 centimeters³

8 0

2 years ago

A sector of a circle of radius is 15Cm, and angle 216 degrees is bent to form a cone. What is base radius of the cone and the ve

-Dominant- [34]

Answer:

Step-by-step explanation:

Radius r = 15

Circumference = 2πr = 30π cm

Circumference of cone = arc length of sector

= 30π × 216°/360°

= 18π cm

Radius of base of cone = 18π/(2π) = 9 cm

Slant height of cone = radius of circle = 15 cm

Height of cone = √(15² - 9²) = 12 cm

3 0

3 years ago

Yee dealin with a dummy wats 3÷3/10

daser333 [38]

Answer:

0.1 I believe would be your answer

3 0

3 years ago

Read 2 more answers

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

2 years ago

How would the mean change if the number 52 replaced the number 12 in the set?

m_a_m_a [10]

Answer:

increase

Step-by-step explanation:

First, we need to find the mean of the given data set without any change.

10 + 61 + 10 + 44 + 21 + 79 + 27 + 12 = 264

264 ÷ 8 = 33

Now that we have the mean, we can find the mean of the data set with the change of 52.

10 + 61 + 10 + 44 + 21 + 79 + 27 + 52 = 304

304 ÷ 8 = 38

From this, we can see that the mean has increased with the change of 12 to 52. Thus, that's the correct option.

hope this helps!

6 0

2 years ago