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GuDViN [60]
2 years ago
12

Use the net to find the surface area of the cylinder, give your answer in terms of pi.

Mathematics
2 answers:
Rainbow [258]2 years ago
6 0

Answer:

104\pi yds

Step-by-step explanation:

The total surface area of the cylinder is

T.S.A=2\pi r^2 +2\pi rh

We substitute r=4yd,h=9yd to obtain;

T.S.A=2\pi \times 4^2 +2\pi 4\times 9

T.S.A=32\pi +72\pi

T.S.A=104\pi yds

postnew [5]2 years ago
5 0

Answer:

The correct answer is last option

surface area = 104 yd²

Step-by-step explanation:

Formula:

Surface area of cylinder = 2πr² + 2πrh

Where r is the radius and h is the  height of cylinder

To find the surface area of cylinder

Here r = 4 yd and h = 9yd

Surface area =  2πr² + 2πrh =  2π * 4 * 4 + 2π *4 *9

 = 32π + 72π = 104π yd²

Therefore the total surface area of given cylinder = 104π yd²

The correct answer is last option .

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On 1st January 2020, Laurie invests P dollars in an account that pays a nominal annual interest rate of 5.5%, compounded quarter
andrezito [222]

Answer:

1) The common ratio =  1.055

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Step-by-step explanation:

1) The given information are;

The date Laurie made the investment = 1st, January, 2020

The annual interest rate of the investment = 5.5%

Type of interest rate = Compound interest

Therefore, we have;

The value, amount, of the investment after a given number of year, given as follows;

Amount in her account = a, a × (1 + i), a × (1 + i)², a × (1 + i)³, a × (1 + i)ⁿ

Which is in the form of the sum of a geometric progression, Sₙ given as follows;

Sₙ = a + a × r + a × r² + a × r³ + ... + a × rⁿ

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Therefore, the common ratio = 1 + i = r = 1 + 0.055 = 1.055

The common ratio =  1.055

2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

㏒2 = n × ㏒(1.055)

n = ㏒2/(㏒(1.055)) ≈ 12.95

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The year in which the amount of money in Laurie's account will become double = year 2032.

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