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Anna11 [10]
3 years ago
13

The value of Acme Stock decreased a total of $40 over the last 5 days. What integer represents the average decrease in stock val

ue each day?
Mathematics
1 answer:
hjlf3 years ago
6 0

Answer:

rewrwefe

Step-by-step explanation:

FFewF

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Help me pls thx<br> ......
melisa1 [442]

Answer:

6x2-2x

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
When find the margin error for the mean of a normally distributed population from a sample what is the critical probability assu
UNO [17]
<span>( 1 - .58)/2 = .21 HERES THE ANSWER 

</span>
5 0
3 years ago
Read 2 more answers
Q A clothing company uses 280 pounds to make 70 shirts at this rate how many buttons with the clothing company used to make 460
Annette [7]

Answer:

1840

Step-by-step explanation:

The number of buttons used in making 1 shirt = 280/70 = 4 buttons

the number of buttons used in making 460 shirts = 460 x 4 = 1840 buttons

3 0
3 years ago
What are the partial products? 617 x 2
12345 [234]

Answer:

b. 1,200 + 20 + 14

Step-by-step explanation:

617

x

2

______

1234

______

1234 aka. 1,200 + 20 + 14

5 0
3 years ago
In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co
sukhopar [10]

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

Education College = 30%

Calculated

Business College = 90/300= 9/30= 0.3 or 30%

Arts College= 120/300= 12/30= 2/5= 0.4 or 40%

Education College= 90/300= 9/30 = 0.3 or 30%

First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= \sqrt{npq\\}

Business College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.4*0.6*300}=  8.49

Education College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Now calculating the previous means with the same number of students

Business College

Mean = np =300*0.35= 105

Arts College

Mean = np =300*0.35= 105

Education College:

Mean = np =300*0.3= 90

Now formulate the null and alternative hypothesis

Business College

90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90     U1: mean ≠ 90

From these we conclude that the  proportions have not changed significantly meaning that it falls outside the critical region.

8 0
3 years ago
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