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3 years ago

Elevii au studiat o schiță a corpului uman. Ei au observat că ar putea trasa pe schiță un

Mathematics

1 answer:

julia-pushkina [17]3 years ago

8 0

Answer:

an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).

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What is7,498 rounded to the greatest place value????

Irina18 [472]

Answer:

7,000

Step-by-step explanation:

The answer is 7,000 because when rounding to the greatest value you basically keep on number and round the others since the 498 is lower than 500 you would keep the 7 and turn the other's into 0's hence 7,000.

4 0

3 years ago

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Find a coefficient of x in -7x, and a coefficient of 9/4y.

garik1379 [7]

Answer:9

Step-by-step explanation:

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3 years ago

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The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.

Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

$\overline{CD} = 12 \: units$

$\overline{C'D'}$

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

$\overline{C'D'} = n \times \overline{CD}$

Option A

If n=3/2, then

$\overline{C'D'} = \frac{3}{2} \times 12 = 3 \times 6 = 18 \: units$

This is true.

Option B

If n=4, then

$\overline{C'D'} = 4 \times 12 = 36 \: units$

This is false.

Option C

If n=8, then

$\overline{C'D'} = 8 \times 12 = 96 \: units$

This too is false.

Option D

If n=2, then

$\overline{C'D'} = 2 \times 12 = 24 \: units$

This is true

Option E

If n=3/4, then

$\overline{C'D'} = \frac{3}{4} \times 12$

$\overline{C'D'} = 3 \times 3 = 9 \: units$

This is also true.

4 0

3 years ago

to rent a building for a school dance ava paid $120 plus $2.50 for each student who attended. If she paid a total cost of $325 h

deff fn [24]

Answer:

82 students

Step-by-step explanation:

8 0

3 years ago

If y=(x^2-4)^5(3x+4)^4

alexira [117]

Answer:

$y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)$

Step-by-step explanation:

$y=(x^2-4)^5(3x+4)^4$

$y'=[\frac{d}{dx}(x^2-4)^5](3x+4)^4+(x^2-4)^5[\frac{d}{dx}(3x+4)^4]$

$y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)$

$y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3$

$y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)$

5 0

2 years ago