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2 years ago

Which of these expressions is equivalent to 3x(x-1)-5(x-1)? Select all that apply.

Mathematics

2 answers:

Maru [420]2 years ago

6 0

Answer:

3x(x-1)-5(x-1)

=3x²-3x-5x+5 (we can count it one by one)

=3x²-8x+5 (we can calculate the same variable)

#i'm from indonesia

hope it helps.

yan [13]2 years ago

4 0

Answer:

$\boxed{3x^2 -8x+5}$

$\boxed{(3x-5)(x-1)}$

Step-by-step explanation:

$3x(x-1)-5(x-1)$

Expand brackets.

$3x(x)+3x(-1)-5(x)-5(-1)$

$3x^2 -3x-5x+5$

Combine like terms.

$3x^2 -8x+5$

$3x(x-1)-5(x-1)$

Take x-1 as a common factor.

$(3x-5)(x-1)$

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Which of the following is the equation for the graph shown?a. x^2/144+y^2/95=1b. x^2/144-y^2/95=1c. x^2/95+y^2/144=1d. x^2/95-y^

Andrews [41]

e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

$\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1$

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

$\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}$

STEP 3: Get the equation of the ellipse

$\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}$

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

$\frac{x^2}{144}+\frac{y^2}{95}=1$

OPTION A

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1 year ago

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Sergeeva-Olga [200]

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Step-by-step explanation:

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I am Lyosha [343]

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