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2 years ago

Which of these expressions is equivalent to 3x(x-1)-5(x-1)? Select all that apply.

Mathematics

2 answers:

Maru [420]2 years ago

6 0

Answer:

3x(x-1)-5(x-1)

=3x²-3x-5x+5 (we can count it one by one)

=3x²-8x+5 (we can calculate the same variable)

#i'm from indonesia

hope it helps.

yan [13]2 years ago

4 0

Answer:

$\boxed{3x^2 -8x+5}$

$\boxed{(3x-5)(x-1)}$

Step-by-step explanation:

$3x(x-1)-5(x-1)$

Expand brackets.

$3x(x)+3x(-1)-5(x)-5(-1)$

$3x^2 -3x-5x+5$

Combine like terms.

$3x^2 -8x+5$

$3x(x-1)-5(x-1)$

Take x-1 as a common factor.

$(3x-5)(x-1)$

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2 years ago

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Alex787 [66]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's use distance formula :

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$\qquad \sf \dashrightarrow \:(x - 1) {}^{2} + 9 = 25$

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2 years ago

Find the geometric mean of the pair of numbers.

Nikolay [14]

Thank you for posting your question here at brainly. Feel free to ask more questions.

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3 years ago

Find four consecutive multiples of 3 such that the product of the first, third, and fourth is 1080

Dovator [93]

Answer:

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Step-by-step explanation:

Let's find the factors of 1,080, as follows:

1,080 Dividing by 2 (1,080/2)

540 Dividing by 2 (540/2)

270 Dividing by 2 (270/2)

135 Dividing by 3 (135/3)

45 Dividing by 3 (45/3)

15 Dividing by 3 (15/3)

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In consequence, we have:

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Let's find out what multiples of 3 there are:

5 * 3 = 15 is a multiple of 3,

And 3 * 3 * 2 * 2 * 2 is remaining.

3 * 2 = 6 is also a multiple of 3,

And 3 * 2 * 2 is remaining

3 * 2 * 2 = 12 is also a multiple of 3.

Therefore, we have 6, 9, 12, and 15, that are the first, second, third and fourth consecutive multiples of 3, such the product of 6, 12 and 15 is 1,080.

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Answer:

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