Question

What is the value of x? 0.9(x+1.4)−2.3+0.1x=1.6 Enter the answer as a decimal in the box.

Answer 1

Consider the equation $0.9(x+1.4)-2.3+0.1x=1.6.$

1. Simplify it:

$0.9x+0.9\cdot 1.4-2.3+0.1x=1.6,\\ 0.9x+1.26-2.3+0.1x=1.6.$

2. Rewrite the equation such that tems with x stay in left side and numbers are in right side:

$0.9x+0.1x=1.6-1.26+2.3,\\ (0.9+0.1)x=2.64,\\ x=2.64.$

Answer: x=2.64.

Answer 2

Answer: The value of x is 2.64.

Explanation:

Since we have given that

$0.9(x+1.4)-2.3+0.1x=1.6$

We need to find the value of x ,so,

We just use the distributive law which says that

$a(b+c)=ab+ac$

and then collect the like terms and solve it ,

So,

$0.9x+1.26-2.3+0.1x=1.6\\\\1x-1.04=1.6\\\\x=1.6+1.04\\\\x=2.64$

So, the value of x is 2.64.