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2 years ago

7

3) Tara sold candles to raise money for new playground equipment at her school.

1 answer:

Ronch [10]2 years ago

3 0

Answer:

Tara's current expression finds how much the school will be keeping. 50 x 2/5 (also written as 50 x 0.4) totals out as 20. $20 is 2/5 of $50. The expression that Tara SHOULD have written to find how much goes to the candle company would be 50 x 3/5 (also written as 50 x 0.6), as this adds up to 30. $30 is 3/5 of $50.

Step-by-step explanation:

50/5 = 10 which means that 1/5 of 50 = 10.

2/5 of 50 ($20) is kept by the school. This is what Tara's expression finds. This means that $30 is sent to the candle company, and can be found with the expression 50 x 3/5.

The decimals are created by dividing the numerator of the fraction by the denominator (I find it easier to do math with decimals).

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Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?

Phantasy [73]

Answer:

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Step-by-step explanation:

Given : $\cos (180^{\circ}-q)=-\cos q$

We have to write which identity we will use to prove the given statement.

Consider $\cos (180^{\circ}-q)=-\cos q$

Take left hand side of given expression $\cos (180^{\circ}-q)$

We know

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Comparing , we get, a= 180° and b = q

Substitute , we get,

$\cos (180^{\circ}-q)=\cos 180^{\circ} \cos (q)+\sin q \sin 180^{\circ}$

Also, we know $\sin 180^{\circ}=0$ and $\cos 180^{\circ}=-1$

Substitute, we get,

$\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0$

Simplify , we get,

$\cos (180^{\circ}-q)=-\cos (q)$

Hence, use difference identity to prove the given result.

7 0

3 years ago

Read 2 more answers

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viktelen [127]

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2 years ago

Please Please Help Me In These Math Questions!!!!’

Harman [31]

Answer:

m∠JLN = 42°

m∠MLK = 90°

m∠KLO = 42°

m∠JLO = 138°

m∠AGE = 160°

Step-by-step explanation:

m∠JLN = $90-48=42$ °

m∠MLK = 90°

m∠KLO = 42° (∠KLO opposite of ∠JLN, Opposite angles are congruent)

m∠JLO = $180-42=138$ °

For the second question, things become somewhat more complex.

We know that ∠GHD = $2x$ ° and ∠AGH $(x+15)$ °.

You correctly calculated that $x=15$ °.

∠AGE is equal to both $180-(x+15)$ ° and $180-2x$ °. Either equation will work just fine.

∠AGE = $180 - (15 + 15) = 180 - 30 = 160$ °

So m∠AGE = 160°

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3 years ago

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chubhunter [2.5K]

The answer is D
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