Our goal is to find the area
area=1/2 times base times height
we know the height is 7.9 but what is the base?
use the pythagorean theorem twice
alrighty
so
remember for legs length a and b and hytponuse c in a right triangle
a²+b²=c²
we need AD and DC
so
AD²+7.9²=9.4²
AD=√25.95
DC²+7.9²=23.2²
DC=√475.83
so
AD+DC=base=(√25.95)+(√475.83)
area=1/2bh
area=1/2((√25.95)+(√475.83))(7.9)
area≈106.28518654591426812803776879893
round to 2 decimal places
area≈106.29 square units
3.9
Hope that helps
You can use the app math.way also
The mean is the average, which is the sum of all the numbers divided by the total numbers there are. I will add them up for you, and then work from there.
184 + 192 + 164 + 200 = 740.
There is 740cm total, but now we need to divide by how many students we have. We have 4 students total.
740/4 = 185.
Your average (mean) height of the students is 185cm.
I hope this helps!
Answer:
there just adding 2 more stars ,, 1 has 2 , 2 has 4, and 3 has 6
Step-by-step explanation:
Answer: Hello your question is incomplete below is the missing part
Which of the following statements about Hannah’s claim is supported by the interval?
A) Hannah is likely to be incorrect because the difference in the sample means was 18.6−14.4=4.218.6−14.4=4.2 hours.
B) Hannah is likely to be incorrect because 9 is not contained in the interval.
C)The probability that Hannah is correct is 0.99 because 9 is not contained in the interval.
D)The probability that Hannah is correct is 0.01 because 9 is not contained in the interval.
E)Hannah is likely to be correct because the difference in the sample means (18.6−14.4=4.2)(18.6−14.4=4.2) is contained in the interval.
Answer : Hannah is likely to be incorrect because 9 is not contained in the interval. ( B )
Step-by-step explanation:
The statement that is supported by the interval in Hannah's claim is that
Hannah is likely to be incorrect because 9 is not contained in the interval.
