A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
Answer:
Step-by-step explanation:
5/3v + 4 + 1/3v= 8.
Multiply each term by 3v
3v(5/3v) + 3v(4) + 3v(1/3v) = 3v(8)
5 + 12v + 1 = 24v
Collecting like terms
12v - 24v = -5 - 1
- 12v = -6
v = -6/-12
v = 1/2
Answer:
8=8
Step-by-step explanation:
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Answer:
2 5/8 inches
Step-by-step explanation:
This is a subtraction problem.
You must subtract 58 1/8 inches from 60 3/4 inches.
We need a common denominator for the fractions.
The LCD of 4 and 8 is 8.
60 3/4 = 60 6/8
58 1/8 = 58 1/8
60 3/4 - 58 1/8 = 60 6/8 - 58 1/8 = 2 5/8
Answer: 2 5/8 inches